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3 years ago

12

There are 108 students in the book club. Last year, each student read 35 books. How many books did the students read altogether

last year?

1 answer:

Shkiper50 [21]3 years ago

8 0

Answer:

3,780 books. also i like ur pfp i love lil baby too

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6.) Use the graph below to answer the following questions:

weqwewe [10]

Answer:

<u>From the graph we see the intercepts are:</u>

(0, 2.3) and (-2.3, 0)

a) <u>The slope is:</u>

m = 2.3/-2.3 = -1

b)<u> y- intercept is</u>

-2.3

c) <u>The line is:</u>

y = -x - 2.3

<u>Note</u>:<em> 2.3 is the approximate number, it could be 2.4 </em>

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3 years ago

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elixir [45]

The first few twin prime pairs are : (3, 5), (5, 7), (11, 13), (17, 19), (29, 31), (41, 43), (59, 61), (71, 73), (101, 103), (107, 109), (137, 139), …etc. FACT : There are 409 Twin

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4 years ago

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Scorpion4ik [409]

Answer:

10:4

35:14

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3 years ago

Find the axis of symmetry:<br> Picture is below.

trapecia [35]

Answer:

x = -3

Step-by-step explanation:

<h3>Axis of symmetry: </h3>

Axis of symmetry is the vertical line that divides the parabola into two equal halves and it passes through the vertex of the parabola.

From the graph, Vertex (-3, 4)

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2 years ago

Help finding derivative

marusya05 [52]

$\bf \displaystyle \cfrac{d}{dx}\left[ \int\limits_{\sqrt{x}}^{\frac{\pi }{2}}~[cos(t^2)]dt \right]\implies \cfrac{d}{dx}\left[ -\int\limits_{\frac{\pi }{2}}^{\sqrt{x}}~[cos(t^2)]dt \right]\\\\\\ \cfrac{d}{dx}\left[ -\int\limits_{\frac{\pi }{2}}^{x^{\frac{1}{2}}}~[cos(t^2)]dt \right]\\\\
-------------------------------\\\\
u=x^{\frac{1}{2}}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}}\\\\\\ \textit{and now, let's use the \underline{2nd fundamental theorem of calculus}}\\\\
-------------------------------\\\\$

$\bf \displaystyle \cfrac{d}{dx}\left[ -\int\limits_{\frac{\pi }{2}}^{u}~[cos(t^2)]dt \right]\impliedby \cfrac{df}{dx}=\cfrac{df}{du}\cdot \cfrac{du}{dx}
\\\\\\
\cfrac{df}{dx}=-cos(u^2)\cdot \cfrac{du}{dx}\implies \cfrac{df}{dx}=-cos(u^2)\cdot \cfrac{1}{2\sqrt{x}}
\\\\\\
\cfrac{df}{dx}=-cos[(\sqrt{x})^2]\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{df}{dx}=-\cfrac{cos(x)}{2\sqrt{x}}$

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3 years ago