A=20
5a-4=3a+36 (subtract 3a from both sides and add 4 to both sides) 
2a=40. Divide 40by 2 
A=20
        
             
        
        
        
well, if the diameter is 5, thus its radius must be half that, or 2.5, and therefore, the radius of the one four times as much will be (4)(2.5).
Let's simply get their difference, since that'd be how much more is needed from the smaller to larger sphere.
![~\hfill \stackrel{\textit{surface area of a sphere}}{SA=4\pi r^2}\qquad \qquad r=radius~\hfill \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\large difference of their areas}}{\stackrel{\textit{radius of (4)(2.5)}}{4\pi (4)(2.5)^2}~~ - ~~\stackrel{\textit{radius of 2.5}}{4\pi (2.5)^2}}\implies 100\pi -25\pi \implies 75\pi ~~ \approx ~~235.62~ft^2](https://tex.z-dn.net/?f=~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsurface%20area%20of%20a%20sphere%7D%7D%7BSA%3D4%5Cpi%20r%5E2%7D%5Cqquad%20%5Cqquad%20r%3Dradius~%5Chfill%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20difference%20of%20their%20areas%7D%7D%7B%5Cstackrel%7B%5Ctextit%7Bradius%20of%20%284%29%282.5%29%7D%7D%7B4%5Cpi%20%284%29%282.5%29%5E2%7D~~%20-%20~~%5Cstackrel%7B%5Ctextit%7Bradius%20of%202.5%7D%7D%7B4%5Cpi%20%282.5%29%5E2%7D%7D%5Cimplies%20100%5Cpi%20-25%5Cpi%20%5Cimplies%2075%5Cpi%20~~%20%5Capprox%20~~235.62~ft%5E2)
 
        
             
        
        
        
Answer:
 24 square feet 
Step-by-step explanation:
Given:
Dorian is spreading mulch on his triangular flowerbed.
The base is 8 feet.
The height is 6 feet. 
Question asked:
How many square feet of mulch will he need for the flowerbed?
Solution:
The base of  triangular flowerbed = 8 feet.
The height of  triangular flowerbed = 6 feet.
now, to find how many square feet of mulch he will need for the flowerbed, we will find area of the triangular flowerbed:-
As we know:

                            
Thus, 24 square feet of mulch he will need for the flowerbed.
 
        
             
        
        
        
The median is the middle number, and we can find that by listing the numbers in order of size.
201, 218, 242, 257, 265, 275, 301.  We can see that the middle number is 257, so 257 is the median.
        
                    
             
        
        
        
Volume of cylinder 
πr^2h
π6^2x11=396π
Volume of sphere 
4/3πr^3
4/3π6^3=288π
396π+288π=684π
=2148.849375