Hello,
y=sin²(cos(2x))
y'=2*sin(cos(2x))*cos(cos(2x))*(-sin(2x)*2)
= -4*sin(cos(2x))*cos(cos(2x))*sin(2x)
5.B
6.D
7.A
8.B
9.A
10.C hsvs whehsg
Step-by-step explanation:
The coefficients of the y terms are -3 and 2. The least common multiple of 3 and 2 is 6. So multiply the first equation by 2 and the second equation by 3, so that the y terms have a coefficient of 6.
4x − 6y = 42
-18x + 6y = 21
The signs are opposite, so add the equations together.
-14x = 63
x = -9/2
Answer:
I used to know how to do this
Step-by-step explanation:
I forgot tho sorry
