All categories

3 years ago

Leftmost digit of two numbers are 8 and 3 which is greater

Mathematics

1 answer:

anastassius [24]3 years ago

6 0

8. 8 is greater than 3 and is all the way to theeft. if it was to the right, you'd need more info

You might be interested in

PLEAE HELP WILL GIVE YOU BRAINLIEST. Simplify 3<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="

gladu [14]

18sqrt(x)
I'm assuming that 3(sqrt(x))5 is equal to 15sqrt(x). If that is the case, just perform the multiplication within each term and treat the sqrt(x) as a variable when you add the all together. It is okay because they are like terms.

7 0

3 years ago

Evaluate |15-15| <br> If you could also explain it to me I’d appreciate.

IRISSAK [1]

your answer is 0

Step-by-step explanation:

3 0

3 years ago

If the expression $3^1 times 9^2 times 27^3 \times 81^4 is simplified to the form 3^n, what is the value of n?

Darina [25.2K]

Answer:

$n=30$

Step-by-step explanation:

Given expression:

$3^1\times 9^2\times 27^3\times 81^4$

The given expression needs to be simplified to the form $3^n$

Applying the exponents rule to simplify.

$3^1\times 9^2\times 27^3\times 81^4$

Writing all numbers as product of 3.

⇒ $3^1\times (3\times3)^2\times (3\times3\times3)^3\times (3\times3\times3\times3)^4$

Writing each in exponents form.

⇒ $3^1\times (3^2)^2\times (3^3)^3\times (3^4)^4$

Using power of a power rule $[\ (a^x)^y=a^{xy}\ ]$

⇒ $3^1\times 3^4\times 3^9\times 3^16$

Using multiplication rule of exponents $[\ a^x\times a^y=a^{x+y}\ ]$

⇒ $3^{1+4+9+16}$

⇒ $3^{30}$

So we have $3^n=3^{30}$

∴ $n=30$

8 0

3 years ago

Divide z by 11. Then, add 8.

yulyashka [42]

This may be the answer,hope it helps

8 0

3 years ago

David works in a department store selling clothing. He makes a guaranteed salary of $250 per week, but is paid a commision on to

MAXImum [283]

Answer:

250 + 0.05 (1500)

250 + 75 = $325 david made i a week with 1500 in sales

250 + 0.05(xx) is how much david would make if he sold xx that week

Step-by-step explanation:

i hope this helped :)

4 0

3 years ago

Read 2 more answers