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german
3 years ago
7

What is the distance, to the nearest whole number, from K (5, 6) to P (1, 1)?

Mathematics
1 answer:
Elza [17]3 years ago
5 0

Answer:

<h3>The answer is 6 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

K (5, 6) P (1, 1)

The distance from K to P is

|KP|  =  \sqrt{ ({5 - 1})^{2} +  ({6 - 1})^{2}  }  \\  =  \sqrt{ {4}^{2} +  {5}^{2}  }  \\  =  \sqrt{16 + 25}  \\  =  \sqrt{41}  \\  = 6.403124

We have the final answer as

<h3>6 units to the nearest whole number</h3>

Hope this helps you

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find a parameterization for a circle of radius 3 with center (-4,4,1) in a plane parallel to the yz plane. write your parameteri
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Answer:

Following are the solution to the question:

Step-by-step explanation:

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3 years ago
How can you add the fractions 3/10 and 2/5? Explain
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= 7/10

The final answer is 7/10~


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2 years ago
15 Pts + Brainliest for the best answer
34kurt

If T is the midpoint of SU, then ST ≅ TU.

Therefore we have the equation:

6x = 2x + 32       <em>subtract 2x from both sides</em>

4x = 32       <em>divide both sides by 4</em>

x = 8

ST = 6x → ST = 6(8) = 48

TU = ST, therefore ST = 48

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<h3>Answer: ST = 48, TU = 48, SU = 96</h3>
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