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andreev551 [17]
3 years ago
7

Borox is loading a freight elevator with 12 boxes: 4 small, 5 medium, and 3 large. A small box and medium box together weigh 20

pounds; a medium box and a large box together weigh 28 pounds; and a small box with a large box together weigh 24 pounds. What is the total weight of the 12 boxes?
Mathematics
1 answer:
Leni [432]3 years ago
7 0

Answer:

30

Step-by-step explanation:

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tresset_1 [31]

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answer is 360

Step-by-step explanation:

multiply length times width

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The Square sand pit in park lot has an area of 16 ft. There is a rope along one side of the pit. How long is the rope?
slavikrds [6]

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Step-by-step explanation:

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3 years ago
at video shack movie rentals cost $3.99 each. the cost of renting three movies and one video game is $.11 less than the cost of
damaskus [11]
x-\ cost\ of\ renting\ video\ game\\
y-\ cost\ of\ tenting\ movie\\\\
3y+1x+11=5x\\
y=3,99\\\\
3*3,99+x+11=5x\\
11,97+x+11=5x\ \ \ | subtract\ x\\
22,97=4x\ \ \ | divide\ by\ 4\\
x=5,7425\$\\\\
For\ renting\ video\ game\ you\ will\ pay\ 5,7425\$.
4 0
3 years ago
I need help on the top one 25 pts
svet-max [94.6K]
The answer to the question

8 0
3 years ago
A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 3 the seco
IceJOKER [234]

Events

• A: an even number is rolled in the first time

,

• B: a number greater than 3 is rolled the second time

The probability of rolling an even number is:

\begin{gathered} P(A)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(A)=\frac{3}{6} \\ P(A)=\frac{1}{2} \end{gathered}

The probability of rolling a number greater than 3 is:

\begin{gathered} P(B)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(B)=\frac{3}{6} \\ P(B)=\frac{1}{2} \end{gathered}

Events A and B are independent, then the probability of one happening after the other is:

\begin{gathered} \text{ P(A and B) = }P(A)\cdot P(B) \\ \text{ Substituting with the values previously found:} \\ \text{ P(A and B) = }\frac{1}{2}\cdot\frac{1}{2} \\ \text{ P(A and B) = }\frac{1}{4} \end{gathered}

8 0
1 year ago
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