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enyata [817]
3 years ago
15

If x=2 what is the perimeter?

Mathematics
1 answer:
Fiesta28 [93]3 years ago
4 0

Answer:

129

Step-by-step explanation:

(4*2^2+8*2)= 32

(3*2^2-5*2+20)=22

(7*2+30)=44

32+31+22+44=129

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40 bricks

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3 1/2×8

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What is the area of the model in the problem?
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A=x^2+12x+27\ units^2

Step-by-step explanation:

we know that

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The area of a rectangle is equal to

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we have

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4 years ago
Select the point that is a solution to the system of inequalities
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The answer is (1,6) so its either A or C since they both have (1,6)

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Paula invests £4500 in a savings account
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Answer:

18.61

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Principle = £4500

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6 0
4 years ago
The
stepan [7]

Answer:

Area = 129.5m^2

Perimeter = 48m

Step-by-step explanation:

Given

See attachment

Required

Determine the area and the perimeter of the garden

Calculating Area

First, we calculate the area\ of\ the\ rectangle

A_1 = L * B

Where:

L = 20-(3.5 +3.5)

B = 7

So:

A_1 = (20 - (3.5 + 3.5)) * 7

A_1 = (20 - 7) * 7

A_1 = 13 * 7

A_1 = 91

Next, we calculate the area of the two semi-circles.

Two semi-circles = One Circle

So:

A_2 = \pi r^2

Where

r = \frac{7}{2}

A_2 = \frac{22}{7} *  (\frac{7}{2})^2

A_2 = \frac{22}{7} *  \frac{49}{4}

A_2 = \frac{22}{1} *  \frac{7}{4}

A_2 = \frac{22*7}{4}

A_2 = \frac{154}{4}

A_2 = 38.5

Area of the garden is

Area = A_1 + A_2

Area = 91 + 38.5

Area = 129.5m^2

Calculating Perimeter

First, we calculate the perimeter of the rectangle

But in this case, we only consider the length because the widths have been covered by the semicircles

P_1 = 2 * L

Where:

L = 20-(3.5 +3.5)

So:

P_1 =2 * (20-(3.5 +3.5))

P_1 =2 * (20-7)

P_1 =2 * 13

P_1 =26

Next, we calculate the perimeter of the two semi-circles.

Two semi-circles = One Circle

So:

P_2 = 2\pi r

Where

r = \frac{7}{2}

P_2 = 2 * \frac{22}{7} * \frac{7}{2}

P_2 = \frac{2 * 22 * 7}{7 * 2}

P_2 = \frac{308}{14}

P_2 = 22

Perimeter of the garden is

Perimeter = P_1 + P_2

Perimeter = 26 + 22

Perimeter = 48m

8 0
3 years ago
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