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Yuliya22 [10]
3 years ago
8

Evaluate the expression. 4C3/14C3

Mathematics
1 answer:
nadezda [96]3 years ago
4 0

Answer:

2/7

Step-by-step explanation:

Multiply the numerator:

4 x 3 = 12

12C

Multiply the denominator:

14 x 3 = 42

42C

Together:

12c/42c

Cancel the common factor:

(Common factor is 6)

2c/7c

Cancel common factor:

(Common factor is C)

2/7

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HELP PLEASE!!!!!!
wel

Pat's average rate of change over the entire trip up the mountain is 41.7, while the cable car's average rate of change over the entire trip up the mountain is 50

<h3>The average annual rate of change</h3>

The given parameters are:

Value in 1990 = $12,500

Value in 2009 = $20,050

The average annual rate of change is then calculated as:

Rate of change = Difference in the values/Difference in the years

So, we have:

Rate of change = (20050 - 12500)/(2009 - 1990)

Evaluate

Rate of change = 397.37

<h3>Pat and cable car</h3>

<u>The complete table of average rate of change</u>

The average rate of change is calculated as:

Average rate of change = Difference in heights at the intervals/Difference in the interval

So, we have:

<em>0 - 2 minutes</em>

Pat = (125 - 0)/(2 - 0) = 62.5

Cable = (100 - 0)/(2 - 0) = 50

<em>2 - 4 minutes</em>

Pat = (200 - 125)/(4 - 2) = 37.5

Cable = (200 - 100)/(4 - 2) = 50

<em>4 - 5 minutes</em>

Pat = (225 - 200)/(5 - 4) = 25

Cable = (250 - 200)/(5 - 4) = 50

So, the complete table is:

Time   0 - 2 minutes     2 - 4 minutes    4 - 5 minutes

Pat           62.5                     37.5                   25

Cable       50                         50                      50

<h3>Is the rate of change constant for Pat? Is it constant for the cable car? </h3>

The rate of change is not constant for Pat, while the rate of change is constant for the cable car

This is so because, we have different values for the rate of change for Pat, while we have only one value for the rate of change for Cable car

<h3>The average rate of change over the entire trip up the mountain</h3>

This is calculated as:

Average rate of change = Difference in heights at the intervals/Difference in the interval

So, we have:

Pat = (250 - 0)/(6 - 0) = 41.7

Cable = (250 - 0)/(5 - 0) = 50

Hence, Pat's average rate of change over the entire trip up the mountain is 41.7, while the cable car's average rate of change over the entire trip up the mountain is 50

Read more about average rate of change at

brainly.com/question/2170564

#SPJ1

6 0
2 years ago
Please answer this question
Gnesinka [82]

Answer:

There are 20 kids total in the class.

Step-by-step explanation:

15/100 × 20 = 3  

You can use direct proportion for any percent calculation.

Compare each number with its percent.

3 i s  15 %  of what number? Let the number be  x

So, 3  represents  15 %  and  x  represents  100 %

x/ 100   =  3/15  

Multiply by  100  to isolate  x

x  = \frac{3 x 100}{15}

x  =  20

Check:  15/ 100 × 20 = 3

3 0
3 years ago
The coordinates of the endpoints of QR are
trasher [3.6K]

Answer:

A, 5.8

Step-by-step explanation:

Q(8,2) and R(5,7)

8 0
3 years ago
How to find the missing measurements ?
ad-work [718]

Answer:

CD = 10

AD = 22

EC = 13

AC = 26

∠CAD = 23°

∠BAC = 47°

∠ADC  =110°

Step-by-step explanation:

A parallelogram is a quadrilateral with two sets of opposite parallel lines.

Which mean in ABCD parallelogram given AB is parallel to DC and BC is parallel to AD.

Now lets find the values required,

CD = AB (Opposite sides are equal in length)

But, AB= 10 (given) therefore CD = 10.

AD = BC (Opposite sides are equal in length)

But, BC= 22 (given) therefore AD = 22.

EC = AE (Diagonals bisect each other)

But, AE= 13 (given) therefore EC = 13

AC = AE + EC

= 13+13

AC =26

∠CAD = ∠BCA (Alternate interior angles are equal)

But, ∠BCA = 23° therefore, ∠CAD = 23°

∠BAC = ∠ACD (Alternate interior angles are equal)

But, ∠ACD = 47° therefore, ∠BAC = 47°

∠ADC + ∠BCD = 180° (Consecutive interior angles)

But,  ∠BCD = 23°+47°=70°

∠ADC = 180°- ∠BCD

           =180°-70°

∠ADC  =110°

5 0
3 years ago
The base of a triangle is 8 cm. What height will make the area greater than 32 cm^2
katen-ka-za [31]
8x>32
x>4
Any height above 4cm, but not equal to 4cm
8 0
3 years ago
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