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Blizzard [7]
3 years ago
7

Lowest common multiple of 9

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0
Is 3.

3×3=9

Hope this helps!
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X=5y-3
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In 2013, the moose population in a park was measured to be 5,100. By 2018, the population was measured again to be 5,200. If the
natka813 [3]

Answer:

P(t) = 5100e^{0.0039t}

Step-by-step explanation:

The exponential model for the population in t years after 2013 is given by:

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This means that P(0) = 5100

So

P(t) = 5100e^{rt}

By 2018, the population was measured again to be 5,200.

2018 is 2018-2013 = 5 years after 2013.

So this means that P(5) = 5200.

We use this to find r.

P(t) = 5100e^{rt}

5200 = 5100e^{5r}

e^{5r} = \frac{52}{51}

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r = 0.0039

So the equation for the moose population is:

P(t) = 5100e^{0.0039t}

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Answer:

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Step-by-step explanation:

blue : red

28      48

Divide each by 4

28/4   48/4

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blue : red

7      : 12

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3 years ago
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