Answer:
Step-by-step explanation:
If k is the number of classes and n is the number of observations, then for number of classes we should select the smallest k such that 2^k > n.
<u>We have n = 50 and:</u>
- 2^5 = 32 < 50
- 2^6 = 64 > 50
As per above described 2 to k rule, we are taking k = 6.
So 6 classes should be used.
You would have to divide and either get a remainder or a decimal
Answer:
I'm gonna have to say False
Step-by-step explanation:
when you round to the nearest tenth you get 90 and 119. 119 - 90 is 29 not 29.99
1) given that those two lines are parallel, we can deduce that 9/45=x/75.
9/45 simplifies to 1/5 so 1/5 = x/75. Cross multiply to get this: 5x = 75.
Divide both sides by 5 to get x.
Final answer: x = 15
2) Again, we can set up a proportion to solve for x because we know the lines are parallel. 24/36=x/12. 24/36 simplifies to 2/3 so 2/3=x/12. Cross multiply to get this: 3x = 24. Divide both sides by 3 to get x.
Final answer: x = 8
