3 years ago

Lowest common multiple of 9

Mathematics

1 answer:

ch4aika [34]3 years ago

3 0

Is 3.

3×3=9

Hope this helps!

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Find the zeros of the polynomial function and state the multiplicity of each.

zheka24 [161]

$\bf f(x) = 4(x + 7)^2(x - 7)^3\implies 0 = 4(x + 7)^2(x - 7)^3
\\\\\\
0=(x+7)^2(x-7)^3\implies 
\begin{cases}
0=(x+7)^7\\
\qquad 0=(x+7)(x+7)\\
\qquad -7=x\\
\qquad -7=x\\
----------\\
0=(x-7)^3\\
\qquad 0=(x-7)(x-7)(x-7)\\
\qquad 7=x\\
\qquad 7=x\\
\qquad 7=x
\end{cases}$

the -7 is found there twice, so it has a multiplicity of 2
the +7 is there thrice, so it has multiplicity of 3

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