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Salsk061 [2.6K]
3 years ago
6

Tanisha used this table to compare the number of school yearbooks purchased

Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:

I can't see the question

Step-by-step explanation:

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Find the midpoint of the segment with the following endpoints. (7,-6) and (4, -10)​
Firlakuza [10]

Answer:

(5.5,-8)

Step-by-step explanation:

(7 + 4)/2 = 5.5

(-6 + -10)/2 = -8

8 0
3 years ago
ANSWER ASAPPP In​ 2000, the population of St. Louis was​ 346,904, and it decreased to​ 319,257 in 2010. If this population decre
mart [117]

Answer:

The​ y-intercept should be 346,904. This is the population for the first (first/last( known year of data. The year 2000 acts as 0 on the graph of the exponential function.

Step-by-step explanation:

I just did it on my homework and it said that my answer is right

8 0
2 years ago
A coin is to be spun 25 times. Let x be the number of spins that result in heads (H). Consider the following rule for deciding w
larisa [96]

Answer:

0.0433

Step-by-step explanation:

Since we have a fixed number of trials (N = 25) and the probability of getting heads is always p = 0.05, we are going to treat this as a binomial distribution.

Using a binomial probability calculator, we find that the probability of obtaining heads from 8 to 17 times is 0.9567 given that the con is fair. The probability of obtaining any other value given that the coin is fair is going to be:

1 - 0.9567 = 0.0433

Since we are going to conclude that the coin is baised if either x<8 or x>17, the probability of judging the coin to be baised when it is actually fair is 4.33%

5 0
3 years ago
-3 1/3 divided by -1/2
Alexandra [31]

Answer:

8/3

Step-by-step explanation:

keep change flip

-3 1/3  (turn the divide into multiplication) and flip the fraction- 1/2 -2/1

-4/3 times -2/1

5 0
3 years ago
I need help with this Factoring Quadratics question.Can someone help me?
antoniya [11.8K]

If you mean "factor over the rational numbers", then this cannot be factored.

Here's why:

The given expression is in the form ax^2+bx+c. We have

a = 3

b = 19

c = 15

Computing the discriminant gives us

d = b^2 - 4ac

d = 19^2 - 4*3*15

d = 181

Note how this discriminant d value is not a perfect square

This directly leads to the original expression not factorable

We can say that the quadratic is prime

If you were to use the quadratic formula, then you should find that the equation 3x^2+19x+15 = 0 leads to two different roots such that each root is not a rational number. This is another path to show that the original quadratic cannot be factored over the rational numbers.

7 0
3 years ago
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