The surface area of the square pyramid shown is 84 square inches. What is the value of $x$ ? Square pyramid with base edge of 6
inches, and a slant height labeled x inches, on a triangular face.
2 answers:
Answer:
4 inches
Step-by-step explanation:
The surface area, A of a right square pyramid is given by :
A = a² + 2as
Where, s = height of each triangular surface = x
a = base edge of pyramid
Substituting values into the equation :
A = 84 in² ; a = 6 in ; Slant height, s = x
84 = 6² + 2(6 * x)
84 = 36 + 2(6x)
84 = 36 + 12x
84 - 36 = 12x
48 = 12x
48/12 = 12x / 12
4 = x
Hence, Slant height, x = 4 inches
Answer:
4 inches
Step-by-step explanation:
The surface area, A of a right square pyramid is given by :
A = a² + 2as
Where, s = height of each triangular surface = x
a = base edge of pyramid
Substituting values into the equation :
A = 84 in² ; a = 6 in ; Slant height, s = x
84 = 6² + 2(6 * x)
84 = 36 + 2(6x)
84 = 36 + 12x
84 - 36 = 12x
48 = 12x
48/12 = 12x / 12
4 = x
Hence, Slant height, x = 4 inches
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Solution
Please note that the statement must be a true representation of the population
It is helpful by knowing it has at least one acute angle
Answer:
40
Step-by-step explanation:
SF of KP to KN = 4
If LM = 32, then we would have to divide 32 by 4 in order to get the missing length of KL.
32 ÷ 4 = 8
Length of KL = 8
Length of LM = 32
Length of KM = 32 + 8 = <u>4</u><u>0</u>
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