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GaryK [48]
3 years ago
7

write a sequence of transformations that maps quadrilateral ABCD onto quadrilateral A"B"C"D" in the picture below

Mathematics
2 answers:
Assoli18 [71]3 years ago
8 0

Answer:  The answer is reflection across the Y-axis followed by a translation of 2 units downwards.

Step-by-step explanation:  We are to write a sequence of transformations that maps quadrilateral ABCD onto quadrilateral A"B"C"D" in the given figure.

First, we will reflect the quadrilateral ABCD along the Y-axis. The, the resulting figure, suppose A'B'C'D'will be just above the quadrilateral A"B"C"D" at a distance of 2 units.

To make the two figures coincide, we bring the quadrilateral A'B'C'D' 2 units below. Then, we will see that the quadrilateral A'B'C'D' will coincide with the quadrilateral A"B"C"D".

Thus, a sequence of transformations is

reflection across the Y-axis followed by a translation of 2 units downwards.

slavikrds [6]3 years ago
4 0
Reflection over the y axis Then a translation of 2 units down
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Jet001 [13]

Answer:

-3 < x < 3

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graph shown below

==============================================

Work Shown:

5|x| + 3 < 18

5|x| + 3 - 3 < 18-3 ... see note 1

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(5|x|)/5 < 15/5 .... note 2

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graph shown below

-----------

note 1: Subtract 3 fom both sides to undo the "+3"

note 2: Divide both sides by 5 to undo the multiplication

note 3: If |x| < k, for some positive number k, then -k < x < k

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