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valina [46]
3 years ago
7

The cylinder and the sphere below have the same radius and the same volume. What is the

Mathematics
1 answer:
oee [108]3 years ago
7 0
The answer would be 8 or A

Step by Step Explanation:

First you have to find the volume of the Sphere.

Set the problem up like this: V = Volume
V= 4/3 • pi (3.14) • 6(3)
= 904.32

Now you have to volume and as stated the volume and radius is the same for both the cylinder and sphere. So now you plug in the answers for the letters.
Formula for (V) Volume of Cylinder is:
V= Pi (3.14) • R (radius) (2) • H (height)
So plug in for what you know
904.32 = 3.14 • 6(2) • H
904.32 = 3.14 • 36 • H
113.04/904.32 = 113.04 • H/113.04
8 = H

The answer is A
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Read 2 more answers
Factorize :3y²-54y+343​
arlik [135]

1 In general, given

a

x

2

+

b

x

+

c

ax

2

+bx+c, the factored form is:

a

(

x

−

−

b

+

b

2

−

4

a

c

2

a

)

(

x

−

−

b

−

b

2

−

4

a

c

2

a

)

a(x−

2a

−b+

b

2

−4ac

​

​

)(x−

2a

−b−

b

2

−4ac

​

​

)

2 In this case,

a

=

3

a=3,

b

=

−

54

b=−54 and

c

=

343

c=343.

3

(

y

−

54

+

(

−

54

)

2

−

4

×

3

×

343

2

×

3

)

(

y

−

54

−

(

−

54

)

2

−

4

×

3

×

343

2

×

3

)

3(y−

2×3

54+

(−54)

2

−4×3×343

​

​

)(y−

2×3

54−

(−54)

2

−4×3×343

​

​

)

3 Simplify.

3

(

y

−

54

+

20

3

ı

6

)

(

y

−

54

−

20

3

ı

6

)

3(y−

6

54+20

3

​



​

)(y−

6

54−20

3

​



​

)

4 Factor out the common term

2

2.

3

(

y

−

2

(

27

+

10

3

ı

)

6

)

(

y

−

54

−

20

3

ı

6

)

3(y−

6

2(27+10

3

​

)

​

)(y−

6

54−20

3

​



​

)

5 Simplify

2

(

27

+

10

3

ı

)

6

6

2(27+10

3

​

)

​

to

27

+

10

3

ı

3

3

27+10

3

​



​

.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

54

−

20

3

ı

6

)

3(y−

3

27+10

3

​



​

)(y−

6

54−20

3

​



​

)

6 Factor out the common term

2

2.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

2

(

27

−

10

3

ı

)

6

)

3(y−

3

27+10

3

​



​

)(y−

6

2(27−10

3

​

)

​

)

7 Simplify

2

(

27

−

10

3

ı

)

6

6

2(27−10

3

​

)

​

to

27

−

10

3

ı

3

3

27−10

3

​



​

.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

27

−

10

3

ı

3

)

3(y−

3

27+10

3

​



​

)(y−

3

27−10

3

​

I hope this help you

​

6 0
3 years ago
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