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2 years ago

The illustration below shows the graph of y as a function of x.

Mathematics

1 answer:

djverab [1.8K]2 years ago

5 0

Answer:

°This is the graph of a nonlinear function.

°The y-intercept of the graph is the function value y=-6.

°The x-intercepts of the graph are located at x=2 and x=6.

°The greatest value of y is y=2, and it occurs when x=4.

°For x between x=2 and x=6, the function value y>0.

Step-by-step explanation:

I had the same question as you, I didn't get it right but i though i would answer this for you!

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P= -24 q= 12 r= -6 a. (pxq):(q+r) b. (pxr):(r-q) what the answer?

kolezko [41]

Step-by-step explanation:

a. ( p × q ) ( q + r )

= ( -24 × 12 ) ( 12 + -6 )

= 288 × 18

= 5184

b. ( p × r ) ( r - q )

= ( -24 × -6 ) ( -6 - 12 )

= ( 144 ) ( -18 )

= -2592

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3 years ago

What is the value of the following expression?2 x [(12 + 2) x 5] + 32 divided by 2 number on top right 3

a_sh-v [17]

The value of the expression is $141.5$

Explanation:

The expression is $2 \times[(12+2) \times 5]+\frac{3}{2}$

The value of the expression can be determined using the rule PEMDAS.

According to the PEMDAS rule, first we need to perform the operation which is within the parenthesis.

Thus, the expression becomes,

$2 \times(14 \times 5)+\frac{3}{2}$

Multiplying the values within parenthesis, we have,

$2 \times70+\frac{3}{2}$

Using PEMDAS, we need to multiply the numbers.

$140+\frac{3}{2}$

Again using PEMDAS rule, divide the number,

$140+1.5$

Finally, using PEMDAS, let us add the values, we have,

$141.5$

Thus, the value of the expression is $141.5$

7 0

3 years ago

A circle has a circumference of 9π what is the diameter?

mixas84 [53]

C=πd where C=circumference, π=the constant pi, and d=diamter

d=C/π and since we are told that C=9π

d=9π/π

d=9

7 0

3 years ago

HELP ASAP PLEASE!!!!!!!

swat32

The answer is:

A. 8

Have a nice day :)

4 0

3 years ago

Read 2 more answers

Plz help me!!!!!!!!!

Over [174]

Answer: $\bold{\dfrac{4\pm \sqrt{6}}{2}}$

Step-by-step explanation:

$\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}$

$.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}$

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3 years ago