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2 years ago

The perimeter of a rectangular painting is 362 CM if the length of the painting is 97 centimeters what is its width

Mathematics

1 answer:

pochemuha2 years ago

4 0

Answer:

Step-by-step explanation:

97+97=194 because a rectangle has 2 long sides.

362-194=168

168/2=84

Width=84 cm

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What is the five number summary for the data set 0,2,2,4,5,5,5,5,7,11

dimaraw [331]

Answer:

The median/middle is 5 and the minimum is 0 and the maximum is 11. The first quartile is 7/5= 1.4 and the second is 4/2 = 2

Step-by-step explanation:

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2 years ago

A catering company loses $110 as a result of delay. The 5 owners of the company must share the loss equally. Which integer repre

san4es73 [151]

What you have to do first is you have 5 owners correct? Well you take anything they're sharing in this case it's delay/debt, so you divide $110 by 5 and you should get $22. This means that each owner would have to pay $22 to the delay.

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3 years ago

Read 2 more answers

90=3(x+8)+2x-4 what is x

Lilit [14]

Answer:

x = 14

Step-by-step explanation:

Solve for x:

90 = -4 + 2 x + 3 (x + 8)

3 (x + 8) = 3 x + 24:

90 = 3 x + 24 + 2 x - 4

Grouping like terms, 3 x + 2 x - 4 + 24 = (2 x + 3 x) + (-4 + 24):

90 = (2 x + 3 x) + (-4 + 24)

2 x + 3 x = 5 x:

90 = 5 x + (-4 + 24)

24 - 4 = 20:

90 = 5 x + 20

90 = 5 x + 20 is equivalent to 5 x + 20 = 90:

5 x + 20 = 90

Subtract 20 from both sides:

5 x + (20 - 20) = 90 - 20

20 - 20 = 0:

5 x = 90 - 20

90 - 20 = 70:

5 x = 70

Divide both sides of 5 x = 70 by 5:

(5 x)/5 = 70/5

5/5 = 1:

x = 70/5

The gcd of 70 and 5 is 5, so 70/5 = (5×14)/(5×1) = 5/5×14 = 14:

Answer: x = 14

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3 years ago

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In the figure, BP is an angle bisector of ∠CBD.

mihalych1998 [28]

Answer:

Step-by-step explanation:

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3 years ago

Jessie is fencing in a rectangular plot outside of her back door so that she can let her dogs out to play. She has 60 feet of fe

DerKrebs [107]

Answer:

Dimensions are length 15 feet and width 30 feet.

Maximum area of the plot is 450 feet².

Step-by-step explanation:

Let the length of the plot = x feet and width = y feet.

Since, the amount of fencing to be applied on the three sides of the plot is 60 feet.

We have,

$2x + y = 60$ i.e. $y=60-2x$

Now, Area of the rectangular plot = Length × Width

i.e. Area of the rectangular plot = $x \times y$

i.e. Area of the rectangular plot = $x\times (60-2x)$

i.e. Area of the rectangular plot = $-2x^2+60x$

<em>Since, the maximum of the quadratic equation $ax^2+bx+c$ will be obtained at $x= \frac{-b}{2a}$ .</em>

Then, the maximum of the area of the plot is at the point $x= \frac{-60}{2\times (-2)}$ i.e. x= 15

Then, maximum area of the rectangular plot = $-2x^2+60x$

i.e. maximum area of the rectangular plot = $-2\times 15^2+60\times 15$

i.e. maximum area of the rectangular plot = -450+900 = 450 feet²

Hence, Maximum area of the plot is 450 feet².

Then, $y=60-2\times 15$ implies $y=60-30$ i.e. y= 30.

Hence, the maximum area is enclosed by the length 15 feet and width 30 feet.

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3 years ago