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3 years ago

I want its solution and the unit is about algebraic fraction.

Mathematics

2 answers:

alexandr1967 [171]3 years ago

7 0

Answer:

9x^2

======

6(x - y)

Step-by-step explanation:

Begin by switching the - to a plus. Switch the x and y in the second denominator.

5x^2 2x^2

===== + ======

6x - 6y 3x - 3y

Pull out the common factors in both denominators. Use the distributive property.

5x^2 2x^2

===== + ======

6(x - y) 3(x - y)

Multiply both the numerator and denominator by 2 on the left had fraction.

5x^2 2*2x^2

===== + ======

6(x - y) 2*3(x - y)

5x^2 4x^2

===== + ======

6(x - y) 6(x - y)

Put both numerators over a common denominator. Notice that the + sign shifts up. It shifts up because both fractions have been changed to a common denominator.

5x^2 + 4x^2

===================

6(x - y)

Combine the two numerators since they are of the same power.

9x^2

======

6(x - y)

poizon [28]3 years ago

5 0

Answer:

3x²/(3x - 9y)

This should be the simplest form.

Step-by-step explanation:

Combine the fractions:

(5x² - 2x²)/((6x - 6y) - (3y - 3x))

Combine like terms:

3x²/(6x - 3x - 6y - 3y)

Solve.

3x²/(3x - 9y)

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Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

3 years ago

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inn [45]

Answer:

(5,-6)

Step-by-step explanation:

This is where the two lines meet. I hope this helps ◕ ◡ ◕

5 0

3 years ago

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Find the minimum value of the following equation:

Mandarinka [93]

Answer:

×=11

Step-by-step explanation:

2×-4×+27-5=0

-2×+22=0

-2×=-22

×=11

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2 years ago

Tracy needs to find the length and width of the equiptment storage room where she works. the room is 2 meters long than it is wi

ElenaW [278]

Rectangle:
P = 2 (L+W) but length is 2 meters longer than wide
then L = W + 2, So
P = 2 (L + W)
24 = 2(W+2+W)
24 = 2 (2 + 2W)
24 = 4 + 4W
So 4W = 24 -4 =20
W = 20/4= 5, L = 5+2= 7

Double check
24 = 2*(5+7) = 2 *12 = 24

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3 years ago

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Please help for brainliest!!:)

grandymaker [24]

9514 1404 393

Answer:

Step-by-step explanation:

If the polynomial has integer coefficients, its complex or radical roots come in conjugate pairs. That is, -√10 is also a root. The four roots mean the polynomial has degree 4. That eliminates all but answer choice C.

Each root 'a' gives rise to a factor (x -a), so the factored polynomial is ...

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