Question

Tracy needs to find the length and width of the equiptment storage room where she works. the room is 2 meters long than it is wide. its perimeter is 24 meters. find the width in meters

Answer 1

Rectangle:
P = 2 (L+W) but length is 2 meters longer than wide
then L = W + 2, So
P = 2 (L + W)
24 = 2(W+2+W)
24 = 2 (2 + 2W)
24 = 4 + 4W
So 4W = 24 -4 =20
W = 20/4= 5, L = 5+2= 7

Double check
24 = 2*(5+7) = 2 *12 = 24

Answer 2

Answer:

the width of the rectangle is, 5 meters

Step-by-step explanation:

Perimeter(P) of the rectangle is given by:

$P = 2(l+w)$                  ....[1]

where,

l is the length and w is the width of the rectangle.

As per the statement:

Tracy needs to find the length and width of the equipment storage room where she works.

The room is 2 meters long than it is wide. its perimeter is 24 meters.

then;

l = w+2

P = 24 meter

Substitute the given values in [1] we have;

$24 = 2(w+2+w)$

Divide both sides by 2 we have;

$12 = 2w+2$

Subtract 2 from both sides we have;

$10 = 2w$

Divide both sides by 2 we have;

5 = w

or

w = 5 meters

Therefore, the width of the rectangle is, 5 meters