Answer:
Solution given:
m∠ADB=(4x−12)°
m∠CDB=(3x+6)°
m∠ADC =?
Since diagonal BD bisect the angle <ADC
so
m∠ADB= m∠ADC
(4x-12)°=(3x+6)°
4x-3x=6-12
x=12+6
x=18°
again.
<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°
So
<u>the m∠</u><u>ADC</u><u> </u><u>=</u><u>1</u><u>2</u><u>0</u><u>°</u>
Answer:
Eleven million one thousand one hundred ninety-five
Answer:
y = $15.5x
Step-by-step explanation:
Given that
Tim earns $31 after 2 hours
$46.5 earns after 3 hours,
And, $62 earns after four hours
So first determine the each hour earnings i.e.
= $31 ÷ 2
= $15.5
In two hours it would be $31 and so on
So here the equation would be
y = $15.5x
Here
y = money amount
x = number of hours
9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
__
If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.
Answer:
24, 14
Step-by-step explanation:
x + y = 38
x = 10 + y
You can substitute (10+y) into the top equation where the x is.
10 + y + y = 38
10 + 2y = 38
2y = 28
y = 14
Now plug 14 in for y in either equation to get x
x = 10 + 14
x = 24