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grin007 [14]
3 years ago
9

Find the product :1) 6/10 × 10/6 × 5/92) 6/10 × 4/3 × 10/20​

Mathematics
2 answers:
Reptile [31]3 years ago
7 0

Hello!

1) 6/10 × 10/6 × 5/9 = 1/10 × 10 × 5/9 = 1 × 5/9 = 5/9 or 0,5

2) 6/10 × 4/3 × 10/20 = 6 × 4/3 × 1/20 = 2 × 4 × 1/20 = 2 × 1/5 = 2/5 or 0,4

Good luck! :)

Kruka [31]3 years ago
6 0

Answer:

<u>1) 5/9 </u>

<u>2) 2/5</u>

<u>Explanation:</u>

1) 6/10 × 10/6 × 5/9=

<u>Multiply all the denominators and all the numerators then simplify</u>= <em>300/540 = 5/9</em>

<em>2)</em>  6/10 × 4/3 × 10/20=

<u>Multiply all the denominators and all the numerators then simplify</u>= 240/600 = 2/5

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PIT_PIT [208]
If we discuss this as if it is a triangle then the "rise" is the vertical side and the "run" is the adjacent side.
So the ratio of the rise to the run is 8 / 15 which equals <span> <span> <span> 0.5333333333 </span> </span> </span>
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4 0
3 years ago
There was 135 buttons in a jar after Robin put more buttons into the jar there were 175 vines in the jar how many more groups of
RSB [31]

Answer:

4 groups of ten

Step-by-step explanation:

175-135=40

5 0
2 years ago
Help pls I got an email from school Bc I didn’t finish this and I need to finish it before next class and I have like 6 more che
denpristay [2]

Answer:

169.25 inches^{2}

7 0
2 years ago
Find the percent of discount. Round to the nearest whole percent.
Margarita [4]

Answer:

Step-by-step explanation:

105.5x100/120=87.91so 100-88 = 22%

4 0
2 years ago
together,sarah's two cats have the same mass as her dog,11 kg.the mass of one cat is 1500 g greater than the mass of the other.
Alika [10]
Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped



6 0
3 years ago
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