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iris [78.8K]
3 years ago
12

What is the total displacement of the object? m

Mathematics
1 answer:
Elan Coil [88]3 years ago
7 0

Answer:What is the total displacement of the object?

562.5 m

Step-by-step explanation:

ed. 2021

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A car travels along a straight road for 30 seconds starting at time t = 0. Its acceleration in ft/sec2 is given by the linear gr
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Let f(x) = cxe−x2 if x ≥ 0 and f(x) = 0 if x < 0. For what value of c is f a probability density function? for that value of
Yuliya22 [10]

The value of c such that the function f is a probability density function is 2

<h3>How to determine the value of c?</h3>

The density function is given as:

f(x) = cxe^(−x^2) if x ≥ 0

f(x) = 0 if x < 0.

We start by integrating the function f(x)

∫f(x) = 1

This gives

∫ cxe^(−x^2) = 1

Next, we integrate the function using a graphing calculator.

From the graphing calculator, we have:

c/2 * (0 + 1) = 1

Evaluate the sum

c/2 * 1 = 1

Evaluate the product

c/2 = 1

Multiply both sides of the equation by 2

c = 2

Hence, the value of c such that the function f is a probability density function is 2

Read more about probability density function at

brainly.com/question/15714810

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The reciprocal of the curvature is called​
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the radius of curvature, R, is the reciprocal of the curvature.

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Your doctor prescribes you to take 400 mg of medicine every eight hours. How many ounces of medicine do you take in a day
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Employees were asked how many times per week they exercised. The frequency table shows the results of the survey.
wlad13 [49]

Answer:

See explanation

Step-by-step explanation:

Given the frequency table

\begin {array}{cccccccccc}\text{Number}&0&1&2&3&4&5&6&7&8\\ \\\text{Frequency}&5&10&2&9&33&12&15&3&1\end{array}

a) The total sum is

5+10+2+9+33+12+15+3+1=90

Create a probability distribution table

\begin {array}{cccccccccc}\text{Number}&0&1&2&3&4&5&6&7&8\\ \\\text{Probability}&\dfrac{5}{90}&\dfrac{10}{90}&\dfrac{2}{90}&\dfrac{9}{90}&\dfrac{33}{90}&\dfrac{12}{90}&\dfrac{15}{90}&\dfrac{3}{90}&\dfrac{1}{90}\end{array}

b) The probability

P(x

c) The probability

P(x=6)=\dfrac{15}{90}=\dfrac{1}{6}

d) The probability

P(x\ge 5)=P(x=5)+P(x=6)+P(x=7)+P(x=8)=\dfrac{12}{90}+\dfrac{15}{90}+\dfrac{3}{90}+\dfrac{1}{90}=\dfrac{31}{90}

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4 years ago
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