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mars1129 [50]
3 years ago
7

I’m struggling a bit on this question, may someone help me please

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

k = 2

Step-by-step explanation:

Use a graphing calculator

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Find the equation of the line that is perpendicular to y = 2x + 8
Natasha2012 [34]

Answer:

\boxed {\boxed {\sf B. \ y= - \frac{1}{2} x-4}}

Step-by-step explanation:

We are given the line y=2x+8. It is in slope-intercept form or y= mx+b, where m is the slope and b is the y-intercept.

The slope of the line is 2.

We want to find the equation that is perpendicular. Perpendicular lines have negative reciprocal slopes.

1. Negate

  • Negate the slope, or switch the sign
  • (+) 2 --> -2

2. Reciprocal

  • Flip the numerator and denominator of the slope.
  • -2/1 --> -1/2

The perpendicular slope is -1/2, so the correct equation must be B.

6 0
2 years ago
I NEED HELP WITH THIS
Taya2010 [7]

Answer:

B.

Step-by-step explanation:

You must first subtract 12 from 27, which marks out two answers. A, and D.

Then, if NAthan traveled 3 times as far s philip, then you would multiply by three. leaving you with the only option being,

B.

7 0
3 years ago
Read 2 more answers
The formula v= u+ atdescribes connections between u: starting velocity a: acceleration t: time v: final velocity a)In a particul
Bess [88]

Answer:

  • 49 = 0 +9.8t
  • t = 5

Step-by-step explanation:

It usually works to follow directions.

a) Substitute the numbers into the formula:

  v = u + at

  49 = 0 +9.8t

b) Solve the equation:

  49/9.8 = t = 5 . . . . . divide by the coefficient of t

6 0
2 years ago
Write a numerical expression for the difference of 100 and x
frosja888 [35]

Answer:

100-x

Step-by-step explanation:

Hope this helps:)

5 0
3 years ago
Please any one help me ​
Ulleksa [173]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Since it's a Trapezoid with its non - parallel sides equal to one another,

\qquad \sf  \dashrightarrow \:\angle A + \angle P = 180

[ By forming co - interior angle pair ]

\qquad \sf  \dashrightarrow \:\angle A +100 = 180

\qquad \sf  \dashrightarrow \:\angle A = 180 - 100

\qquad \sf  \dashrightarrow \:\angle A = 80

Now, similarly,

\qquad \sf  \dashrightarrow \:\angle A + \angle R = 180

\qquad \sf  \dashrightarrow \: \angle R + 80 = 180

\qquad \sf  \dashrightarrow \: \angle R  = 100

Similarly,

\qquad \sf  \dashrightarrow \angle K + \angle R = 180

\qquad \sf  \dashrightarrow \angle K + 100 = 180

\qquad \sf  \dashrightarrow \angle K  = 80

3 0
2 years ago
Read 2 more answers
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