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anzhelika [568]
3 years ago
9

Need help please answer fast

Mathematics
2 answers:
Zarrin [17]3 years ago
5 0

Answer:

question is not showing sorry

kiruha [24]3 years ago
4 0
It’s not showing the photo
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PLEASE HELP I HAVE TO SUBMIT IN AN HOUR
olga55 [171]

The answer is 3x - 1

                                                                 

3 0
3 years ago
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9−4= tysryghj yhuhyay5y65y
White raven [17]

Answer:

5

Step-by-step explanation:

idek how to explain

4 0
3 years ago
Translate this verbal expression into an algebraic equation and solve: thirteen less than twice the sum of a number and six is 4
Vesna [10]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the verbal expression

''Thirteen less than twice the sum of a number and six is 47''.

Let us break down the verbal expression into an algebraic equation

  • Let the number be = n
  • Twice the number n = 2n
  • Sum of twice the number and six = 2n+6
  • Thirteen less than twice the sum of a number and six = 2n+6-13

And finally

Thirteen less than twice the sum of a number and six is 47:

2n+6-13 = 47

Therefore, the equation is:2n+6-13 = 47

Solving the algebraic expression

solving the equation for 'n'

2n+6-13 = 47

2n-7=47

Add 7 to both sides

2n-7+7=47+7

Simplify

2n=54

Divide both sides by 2

\frac{2n}{2}=\frac{54}{2}

Simplify

n=27

7 0
3 years ago
What's the difference between -40ft and 3000ft
Vladimir79 [104]

Answer:

2960 ft.........is the difference between -40ft and 3000ft

3 0
3 years ago
Look at the image. (calculus)
mash [69]
<h3>Answer: Choice H)  2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is \sin^2 x + \cos^2x = 1

If we were to isolate sine, then,

\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, \cos x = \sqrt{1-\sin^2x}\\\\

Cosine is also positive in this quadrant.

-------------

So,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2

Therefore,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2

is an identity as long as 0 < x < pi/2

5 0
2 years ago
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