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dalvyx [7]
3 years ago
6

If, in a quadratic equation, the values of a and c have opposite signs, the solutions of the equation are real numbers.

Mathematics
1 answer:
Virty [35]3 years ago
4 0
Ax²+bx+c=0 , a>0, c<0 (or a<0, c>0)
D=b²-4ac ≥ 0 always will be positive
because negative*positive = negative, 
a*c -negative, so (-4ac) positive 
So,
<span>If, in a quadratic equation, the values of a and c have opposite signs, the solutions of the equation are real numbers. 
</span>True
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If 2x^2+5x-12 = (2x-3)(x+4), which equation(s) should be solved to find the roots of 2x^2+5x-12=0? Check all that apply.
Fynjy0 [20]

ANSWER

2x-3=0

and

x+4=0

EXPLANATION

Given that:

2 {x}^{2}  + 5x - 12 = (2x - 3)(x + 4)

Then to find roots of

2 {x}^{2}  + 5x - 12 = 0

is the same as finding the roots of

(2x - 3)(x + 4) = 0

By the zero product property, we must have either,

2x - 3 = 0 \: or \: x + 4 = 0

Hence the equations that must be solved to find the roots are:

2x-3=0

and

x+4=0

5 0
3 years ago
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Tamara says that 15÷3=5. is she correct? Explain
Alex787 [66]
There are 5 groups of 3 in the number 15, so 15/3=5
4 0
3 years ago
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Please explain how to solve for x in the attached photo.
natulia [17]

Answer:

x = 24°

Step-by-step explanation:

the sum of the interior angles in a triangle = 180°

so:

(2x + 5°) + 64° + 3x - 9° = 180°

combine like terms:

5x + 60° = 180°

subtract 60° from each side of the equation:

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5 0
3 years ago
I need more help thank
Soloha48 [4]

Answer:

B. 24

Step-by-step explanation:

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9x - 18 = 6x + 54

Collect like terms

9x - 6x = 18 + 54

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Divide both sides by 3

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4 0
3 years ago
PLEASE HELP!
Alexeev081 [22]
Rewrite as:
4y=x^2-12x+68
divide by four:
y= x^2/4-3x+17
your answer would be 
(6,8)
3 0
4 years ago
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