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3 years ago

The diagonals of a square are _____ each other

Mathematics

2 answers:

Soloha48 [4]3 years ago

8 0

Answer:

The last option. D

Step-by-step explanation:

A. incorrect

B. a square is equal with its sides

And option C is also incorrect so it will be D

"perpendicular bisectors of" with is correct because all the sides of a square at equal with eachother

patriot [66]3 years ago

4 0

Answer: d) perpendicular bisectors of

Step-by-step explanation:

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Organize from least to greatest

dedylja [7]

Answer:

y=31x/15 < y=27x/13 < y=15x/7 < y=13x/6 < y=11x/5 < y=21x/9 (=7x/3) < y=19x/8

Step-by-step explanation:

since all equations base on a linear, simple expression of x, we can simply compare the fractions.

in general, the bigger the number at the bottom, the smaller the individual fraction. that is our first indicator.

we then notice that many fractions represent the value of 2 plus one fraction.

31/15 = 2 1/15

27/13 = 2 1/13

15/7 = 2 1/7

13/6 = 2 1/6

11/5 = 2 1/5

the only exceptions are 21/9 and 19/8

but 21/9 is actually 7/3 = 2 1/3

and fits therefore into the list above.

that leaves 19/8 = 2 3/8.

the list above can be sorted based on the single fraction at the end (remember, the bigger the number at the bottom, the smaller the value). so, from least to greatest :

2 1/15 (31/15)

2 1/13 (27/13)

2 1/7 (15/7)

2 1/6 (13/6)

2 1/5 (11/5)

2 1/3 (7/3 = 21/9)

where did now 2 3/8 fit in ?

well, 3/8 is almost 1/2 (so, relatively big), and we start our comparison with the biggest number in the list so far :

1/3 (from 2 1/3).

what is bigger - 1/3 or 3/8 ?

let's find the smallest number that can be divided by 3 and by 8. that would be 24. so now we bring both fractions to the same base of 24.

1/3 = 8/24

3/8 = 9/24

=> 3/8 > 1/3

and therefore, 19/8 is the largest value and at the end of the list.

5 0

3 years ago

Each test contains 20 questions. In average, it takes a person to take each test 40 minutes. If I was to get stuck in one out of

kondor19780726 [428]

I think the answer is 144 minutes

4 0

3 years ago

A recent study examined hearing loss data for 1981 U.S. teenagers. In this sample, 369 were found to have some level of hearing

ruslelena [56]

Answer:

There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.

P-value=0.12

Step-by-step explanation:

We have to perform a test of hypothesis on the proportion.

The claim is that the proportion of US teens that have some level of hearing loss differs from 20%.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.20\\\\H_a:\pi\neq0.20$

The significance level is assumed to be 0.05.

The sample, of size n=1981, has 369 positive cases. Then, the proportion is:

$p=X/n=369/1981=0.186$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.2*0.8}{1981}}=\sqrt{ 0.000081 }= 0.009$

Now, we can calculate the statistic z:

$z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.186-0.20+0.5/1981}{0.009}=\dfrac{-0.014}{0.009}=-1.556$

The P-value for this two-tailed test is:

$P-value=2*P(z$

The P-value is below the significance level, so the effect is not significant. The null hypothesis failed to be rejected.

There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.

7 0

3 years ago

The question is in the image. I

Butoxors [25]

That is right letter b and ir letter c 3-2

4 0

2 years ago

Please help I will mark you as brainlist it’s emergency

Nitella [24]

Answer:

Step-by-step explanation:

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6 0

3 years ago

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