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3 years ago

Just to make sure...are these correct?

Mathematics

2 answers:

Tema [17]3 years ago

8 0

Answer:

Step-by-step explanation:

|-138| = 138

|5/2| = |2.5| = 2.5

|9 5/8| = |9.625| = 9.625

|18.45| = 18.45

|113| = 113

Correct order would be:

|-138|, |113|, |18.45|, |9 5/8|, |5/2|

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Mrac [35]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

yes they are correct

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The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United Sta

earnstyle [38]

Answer:

The probability that none of the meals will exceed the cost covered by your company is 0.2637.

Step-by-step explanation:

A hyper-geometric distribution is used to define the probability distribution of k success in n samples drawn from a population of size N which include K success. Every draw is either a success of failure.

The random variable X = number of meals that will exceed the cost covered by the company.

The random variable X follows a hyper-geometric distribution.

The information provided is:

N = 15

K = 3

n = 5

k = 0

The probability mass function of a hyper-geometric distribution is:

$P(X=k)=\frac{{K\choose k}{N-K\choose n-k}}{{N\choose n}}$

Compute the probability that none of the meals will exceed the cost covered by your company as follows:

$P(X=0)=\frac{{3\choose 0}{15-3\choose 5-0}}{{15\choose 5}}=\frac{1\times 792}{3003}=0.2637$

Thus, the probability that none of the meals will exceed the cost covered by your company is 0.2637.

3 0

3 years ago

How do you find the area of a regular polygon?

weqwewe [10]

Each of the triangles are equal in base length, height, and area. Remember the formula for the area of a triangle. The area of any triangle is 1/2 times the length of the base (which, in the polygon, is the length of a side) multiplied by the height (which is the same as the apothem in regular polygon)

8 0

3 years ago

Can someone please help me ASAP

charle [14.2K]

Answer:

(4,12)

(-1,-3)

Step-by-step explanation:

x^2 - y = 4

y = 3x

Use substitution. Substitute 3x for y in the first equation

x^2 - (3x) = 4

x^2 -3x =4

Subtract 4 from each side

x^2 -3x -4 = 4-4

x^2 -3x-4 =0

Factor

(x-4) (x+1) =0

Using the zero product property

x-4 =0 x+1 =0

x=4 x=-1

Now to find y for each x solution

x=4

y =3x = 3(4) =12

(4,12)

x=-1

y =3x = 3(-1) =-3

(-1,-3)

4 0

3 years ago

Ms. Martinez drove 20 miles in March. She drove 5 times as many miles in March as she did in January. She drove 4 times as many

SVETLANKA909090 [29]

Answer:

825/3 = 275 which is how many miles she drove in January.

275*4= 1100 which is how many miles she drove in February.

Ms. Turner drove 1100 miles in February.

Step-by-step explanation:

3 0

3 years ago

Pls help with 29..tank you

trapecia [35]

Answer:

See below

Step-by-step explanation:

Let the 2 roots be A and A^2.

Then A^3 = c/a and A + A^2 = -b/a.

Using the identity a^3 b^3 = (a + b)^3 - 3ab^2 - 3a^2b:-

A^3 + (A^2)^3 = ( A + A^2)^3 - 3 A.A^4 - 3 A^2. A^2

= (A + A^2)^3 - 3A*3( A + A^2)

Substituting:-

c/a + c^2/a^2 = (-b/a)^3 - 3 (c/a)(-b/a)

Multiply through by a^3:-

a^2c + ac^2 = -b^3 + 3abc

Factoring:-

ac(a + c) = 3abc - b^3

This is not the formula required in the question but let's see if the formula in the question reduces to this. If it does we have completed the proof.

a(c - b)^3 = a(c^3 - 3c^2b + 3cb^2 - b^3) = ac^3 - 3ac^2b + 3acb^2 - ab^3

c(a - b)^3 = c(a^3 - 3a^2b + 3ab^2 - b^3) = ca^3 - 3a^2bc + 3acb^2 - cb^3.

These are equal so we have

ca^3 - 3a^2bc + 3acb^2 - cb^3 = ac^3 - 3abc^2 + 3acb^2 - ab^3

The 3acb^2 cancel out so we have:-

a^3c - ac^3 = 3a^2bc - 3abc^2 + b^3c - ab^3

ac(a^2 - c^2) = 3abc( a - c) + b^3(c - a)

ac(a + c)(a -c) = 3abc(a - c) - b^3 (a - c)

Divide through by (a - c):-

ac(a + c) = 3abc - b^3 , which is the result we got earlier.

This completes the proof.

3 0

3 years ago

Read 2 more answers

Just to make sure...are these correct?​

Just to make sure...are these correct?