The difference between the plant and animal cells is in their structures, and this makes their functions to differ. Some organelles are present in the plant cell which are absent in the animal cell and vice versa. The presence/absence of these organelles impact the kind of functions that can be carried out by each cell.
- The plant cell has a rigid cell wall made of polysaccharides while the animal cell lacks cell wall. The cell wall serves supportive functions in the plant and gives it a shape. Animal cells are more or less round in shape.
- Plant cells have chloroplasts while it is absent in the animal cell. the chloroplast contains chlorophyll, a green pigment that is responsible to absorbing radiant energy, As such, the chloroplast enables plant cells to carry out photosynthesis. Animals cells cannot synthesize their own foods.
- Plant cells have large central vacuole that stores water and other contents while animal cells have small vacuole
- Animal cells have centrioles while plant cells do not. The centrioles make mitotic division different between the two cells, although, the same result is obtained at the end of the day.
More on the differences between plant and animal cells can be found here: brainly.com/question/637711
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pH of the Sr(OH)₂ solution : 12.6
<h3>Further explanation </h3>
pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.
pH = - log [H⁺]
Sr (OH) ₂ solution is a base with valence 2, so we determine the pOH from the OH ion concentration - which is expressed by pOH = - log [OH -]. After that we determine the pH value from the relationship:
[H⁺] [OH⁻] = Kw=10⁻¹⁴
pH + pOH = 14
Sr(OH)₂⇒Sr²⁺+2OH⁻
From equation [Sr(OH)₂] : [OH⁻]=1 : 2, so [OH⁻]=
Answer:
Explanation:
Hello there!
In this case, according to the given chemical reaction:
CaCO3(s)→CaO(s)+CO2(g)
In which the amounts are unfortunately given, we can however, assume the information of similar problems so you can further modify the numbers but follow the same work:
CaCO3 = 25.3 g
CaO = 14.9 g
CO2 = 33.7 g
Thus, since just CO2 is involved on the equilibrium expression because CaCO3 and CaO are solid, we can compute the moles of the CO2 at equilibrium and further compute the concentration in the 9.0-L vessel:
Thus, we proceed with the equilibrium expression to obtain:
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