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kirill115 [55]
3 years ago
12

Period 1- 6th Grade Team A (2020-2021)

Mathematics
2 answers:
Bumek [7]3 years ago
5 0
Interesting ? Your schedule seems very filling, I guess. What are we supposed to do with it?
ryzh [129]3 years ago
3 0
Do you have a question??
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The perimeter of a square is 3 1/3 mi, and its side is 5/6 mi. Find its area
pychu [463]
Area = side * side
5/6 * 5/6
= 25/36
6 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y2
HACTEHA [7]

This question is incomplete, the complete question is;

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y2 = 2x, x = 2y; about the y-axis

Answer:

V = π (512/15)

Step-by-step explanation:

Given that;

region of rotation

y² = 2x, x = 2y

Region is rotated about y-axis as shown in the image

for the point of intersection,

y²/2 = 2y

y² - 4y = 0

y(y-4) = 0

∴ y = 0, y = 4

so the region lies in 0 ≤ y ≤ 4

Now cross section area of washer is

A(y) = π(outer radius)² = π(inner radius)²

A(y) = π(2y)² - π(y²/2)²

A(y) = π(4y²) - π(y⁴/4)

A(y) = π(4y² - (y⁴/4))

now volume of the solid of revolution is

V = ⁴∫₀ A(y) dy

V = ⁴∫₀ π(4y² - (y⁴/4))dy

V =  π {4⁴∫₀ y² - 1/4⁴∫₀y⁴ dy }

V = π { 4/3 [y³]₀⁴ - 1/20 [y⁵]₀⁴ }

V = π { 4/3 [4]₀⁴ - 1/20 [4]₀⁴ }

V = π { 4/3 [64]₀⁴ - 1/20 [1024]₀⁴ }

V = π { 256/3 - 1024/20 }

V = π { (5120 - 3072) / 60 }

V = π (512/15)

8 0
3 years ago
A painter leans a 12-foot ladder against a house. The base of the ladder is
tatiyna

11.3 feet.

12 squared (144) minus 4 squared (16) is equal to 128. The square root of 128 is approximately 11.3.

8 0
3 years ago
Solve for x in the equation X^2 - 8X + 41= 0
BaLLatris [955]

Answer:

The equation has two solutions for x:

<u>x₁ = (8 + 10i)/2</u>

<u>x₂ = (8 - 10i)/2</u>

Step-by-step explanation:

Let's use the quadratic formula for solving for x in the equation:

X^2 - 8X + 41= 0

x² - 8x + 41 = 0

Let's recall that the quadratic formula is:

x = -b +/- (√b² - 4ac)/2a

Replacing with the real values, we have:

x = 8 +/-  (√-8² - 4 * 1 * 41)/2 * 1

x = 8 +/-  (√64 - 164)/2

x = 8 +/-  (√-100)/2

x = 8 +/-  (√-1 *100)/2

Let's recall that √-1 = i

x = 8 +/- 10i/2

<u>x₁ = (8 + 10i)/2</u>

<u>x₂ = (8 - 10i)/2</u>

8 0
3 years ago
Which expression is not equivalent to 2/3 x4
Ksenya-84 [330]

Answer:

I don't know I need the answer choices

Step-by-step explanation:

3 0
2 years ago
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