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nadya68 [22]
3 years ago
12

Which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7

Mathematics
1 answer:
LiRa [457]3 years ago
5 0
<h2>The product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}</h2>

Step-by-step explanation:

We have,

\dfrac{7x}{x-4}.\dfrac{x}{x+7}

To find, the product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = ?

∴ \dfrac{7x}{x-4}.\dfrac{x}{x+7}

= \dfrac{7x.x}{(x-4)(x+7)}

= \dfrac{7x^2}{(x(x+7)-4(x+7)}

= \dfrac{7x^2}{x^2+7x-4x-28}

= \dfrac{7x^2}{x^2+3x-28}

Thus, the product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}

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Answers:
Vertex: (2,-1)
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3 0
3 years ago
What is the product of seven plus two and eight minus two
mr_godi [17]

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54

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Help please I don’t understand this question!!!
icang [17]
To find the mean add up all the numbers and divide. The mean absolute deviation is the difference.
3 0
3 years ago
I’m confused on this one
dedylja [7]

It's a parallelogram so if one angle is 90 degrees they all will be because of transverse angles and all that good stuff.


So we're given the diagonal of a rectangle and one side and we're asked to find the other. The diagonal of a rectangle is the hypotenuse of the right triangle whose legs are the sides of the rectangle. So this is a Pythagorean Theorem question in disguise:


AB^2 + AD^2 = BD^2


AD^2 = BD^2 - AB^2


AD = \sqrt{ BD^2 - AB^2 }


AD = \sqrt{149^2 - 51^2} = \sqrt{19400} = 140


Answer: 140 cm


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3 0
3 years ago
-18=-10-1.5m<br> can someone help
Brums [2.3K]

Answer:

<h2><u><em>m= 16/3</em></u></h2>

Step-by-step explanation:

-18=-10-1.5m

-18+10=-1.5m

-8=-1.5m

m=-8:(-1.5)

m=80:15

m= 16/3

4 0
2 years ago
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