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daser333 [38]
4 years ago
9

I need 3 questions answered please.​

Mathematics
1 answer:
kakasveta [241]4 years ago
8 0

Answer:

3) \:  \: 113 {ft}^{2}

4) \: false

5) \: 70 {ft}^{2}

Step-by-step explanation:

3) Area of a circle is

\pi \times  {r}^{2}

Where r = 6

Thus,

area =   \frac{22}{7}  \times  {6}^{2}

area =  \frac{22}{7}  \times 36

area = 3.143 \times 36

area = 113 {ft}^{2} \: (nearest \: whole \: number)

4) False

Area of a circle is measured by the formula below:

area = \pi \times  {r}^{2}

5) The formula for calculating the area of a rectangle is given thus:

area \: of \: a \: rectangle = l \times w

Where, l = 10ft; w = 7ft

area = 10ft \times 7ft = 70 {ft}^{2}

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Geometry proofs! 100+ points!
Leona [35]
1. BC/CD = AC/CE                                1. Given
2. <BCA is congruent to <ECD              2. Vertical angles are congruent
3. Tr.ACB is congr to Tr.ECD                 3. SAS Similarity
5 0
3 years ago
Read 2 more answers
Encuentra la ecuacion de la parabola con vertice en el origen y foco en las cordenadas 0,1en su forma ordinaria y general
marusya05 [52]

Answer:

x^{2}=4y

y=\frac{1}{4}x^{2}

Step-by-step explanation:

Forma ordinaria

La ecuación de la parabola de manera ordinaria está dada por:

(x-h)^{2}=4p(y-k) (1)  

Donde:

  • (h,k) es la coordenda del vértice, en nuestro caso (0,0) ya que está en el origen.
  • (h,k+p) es la coordenda del foco, en nuestro caso (0,1).

Por lo tanto h = 0, k = 0 y p = 1.

Remplazando estos valores en la ecuación de la parábola, tenemos:

(x-0)^{2}=4*1(y-0)

x^{2}=4y (2)

 

Forma general  

La forma general de una parábola esta dada por la siquiente ecuación

y=ax^{2}+bx+c

Reordenando la ecuación (2) tenemos:

y=\frac{1}{4}x^{2}

Espero esto te haya ayudado!

5 0
3 years ago
How do I find the symmetry
Novay_Z [31]
Symmetry is the same as the one side of the graph but it is fliped on the X-axis
3 0
3 years ago
DESPERATE PLEASE ANSWER FAST
Nonamiya [84]

Answer:

DESPERATE PLEASE ANSWER FAST

(please show picture)

Use the data to create a scatter plot.

Savings Account Balance for a Given Year

PointMove

UndoRedoReset

Time (years)Savings account balance ($)

1

2

3

4

5

6

7

8

9

10

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1400

1600

1800

2000

2200

2400

2600

2800

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3400

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3800

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0

Time (years)

Savings account balance ($)

1

1300

2

2500

3

3600

4

4000

5

2200

6

1800

7

3200

8

9000

Step-by-step explanation:

DESPERATE PLEASE ANSWER FAST

(please show picture)

Use the data to create a scatter plot.

Savings Account Balance for a Given Year

PointMove

UndoRedoReset

Time (years)Savings account balance ($)

1

2

3

4

5

6

7

8

9

10

200

400

600

800

1000

1200

1400

1600

1800

2000

2200

2400

2600

2800

3000

3200

3400

3600

3800

4000

4200

0

Time (years)

Savings account balance ($)

1

1300

2

2500

3

3600

4

4000

5

2200

6

1800

7

3200

8

9000

4 0
3 years ago
Can someone please help me?? Im not quite sure how to get this answer.
nekit [7.7K]

Answer:

C. 54π + 20.25√3 cm²

Step-by-step explanation:

The shaded area can be split into two areas: a sector and an isosceles triangle.

Area of a sector is:

A = (θ/360°) πr²

where θ is the central angle and r is the radius.

Area of an isosceles triangle can be found with SAS formula:

A = ½ ab sin θ

where a and b are two sides of a triangle and θ is the angle between them.

In this case, r = a = b = 9 cm.  The central angle of the sector is 240°, and the vertex angle of the triangle is 120°.  Therefore, the total area is:

A = (240°/360°) π (9 cm)² + ½ (9 cm) (9 cm) sin 120°

A = 54π + 20.25√3 cm²

5 0
3 years ago
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