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2 years ago

BIDEN OR TrUmP have a nice day

Mathematics

2 answers:

lana [24]2 years ago

6 0

Answer:

biden

Step-by-step explanation:

sammy [17]2 years ago

3 0

Answer:

BIDEN

Step-by-step explanation:

no trump hehehhehehe

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Please help last question:((

jasenka [17]

Answer:

7. C(N(h))=33hx+460h

8. about $13.94 is the cost

Step-by-step explanation:

7. C(x)=(33x+460)(N(h))=(N(40)h)--C(x)=(33x+460)(40h)--C(x)=1320hx+18400h--simplified to C(N(h))=33hx+460h

8. C(N(10))=33(10)x+460(10)--C(N(10))=330x+4600--4600/330=about13.94

5 0

3 years ago

If -y-2x^3=Y^2 then find D^2y/dx^2 at the point (-1,-2) in simplest form

algol13

Answer:

$\frac{d^2y}{dx^2} = \frac{-4}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-y - 2x³ = y²

Rate of change of tangent line at point (-1, -2)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Basic Power Rule]: $-y'-6x^2=2yy'$
[Algebra] Isolate y' terms: $-6x^2=2yy'+y'$
[Algebra] Factor y': $-6x^2=y'(2y+1)$
[Algebra] Isolate y': $\frac{-6x^2}{(2y+1)}=y'$
[Algebra] Rewrite: $y' = \frac{-6x^2}{(2y+1)}$

Step 3: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{-12x(2y+1)+6x^2(2y')}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x+12x^2y'}{(2y+1)^2}$
[Derivative] Back-Substitute y': $y'' = \frac{-24xy-12x+12x^2(\frac{-6x^2}{2y+1} )}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x-\frac{72x^4}{2y+1} }{(2y+1)^2}$

Step 4: Find Slope at Given Point

[Algebra] Substitute in x and y: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(-1)^4}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(1)}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Multiply: $y''(-1,-2) = \frac{-48+12-\frac{72}{-4+1} }{(-4+1)^2}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{(-3)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{9}$
[Pre-Algebra] Divide: $y''(-1,-2) = \frac{-36+24 }{9}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-12}{9}$
[Pre-Algebra] Simplify: $y''(-1,-2) = \frac{-4}{3}$

6 0

2 years ago

Is my answer correct?

Alexandra [31]

Yes your answer would be correct! :)

8 0

3 years ago

Read 2 more answers

Consider the quadratic function: f(x) = x2 – 8x – 9

Bumek [7]

Solved in quadratic function
The answer :
X=(9,-1)

7 0

2 years ago

How do I solve 1 1/2c = 6

quester [9]

$1 \frac{1}{2} c = 6 \\ \\ \frac{2 + 1}{2} c = 6 \ / \ convert \ to \ improper \ fraction \\ \\ \frac{3}{2} c = 6 \ / \ simplify \\ \\ \frac{3c}{2} = 6 \ / \ simplify \\ \\ 3c = 6 \times 2 \ / \ multiply \ each \ side \ by \ 2 \\ \\ 3c = 12 \ / \ simplify \\ \\ c = \frac{12}{3} \ / \ divide \ each \ side \ by \ 3 \\ \\ c = 4 \ / \ simplify \\ \\$

So, your answer to this problem is c = 4.

6 0

3 years ago

Read 2 more answers