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3 years ago

The ratio of boys to girls at a movie is 4:5. If there are 15 girls, how many boys are at the movie?

Mathematics

1 answer:

melamori03 [73]3 years ago

8 0

Answer:

There are 12 boys at the movie.

Step-by-step explanation:

Key skills needed in order to solve: Proportions, Ratios, and Multiplication

1) The ratio is 4 boys : 5 girls --> It can be written as a fraction --> 4/5

2) If there are 15 girls, we need to find the number of boys. let's say x is the number of boys when there are 15 girls. The ratio would then be x/15

3) Make a proportion --> $\frac{4}{5}$ = $\frac{x}{15}$

You have to cross multiply here. You do the first fraction's numerator times the second fraction's denominator, and the first fraction's denominator times the second fraction's numerator.

4) This means you have to do: 4(15) = 5(x)

5) Multiply it out --> 60=5x

6) Divide by 5 and you will get x=12

Therefore there are 12 boys at the movie.

Hope you understand and have a nice day!! :D

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The table below shows the typical hours worked by employees at a company. A new employee is offered an annual salary of $37,000.

Mademuasel [1]

Answer:

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Step-by-step explanation:

As per table, hours worked per week:

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Comparing with annual salary, we see:

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3 years ago

A cylinder has a diameter of 6 feet. the volume of the cylinder is 36/5π cubic feet.

Anton [14]

Answer:

Height of cylinder is $\frac{4}{5}\ ft$ .

Step-by-step explanation:

Diameter of cylinder, D = 6 feet

Relation between Radius, R and diameter, D is given by:

$R = \dfrac{D}{2}$

So, radius, R = $\frac{6}{2} \Rightarrow 3$ feet

Let height of cylinder be $h$ feet.

Formula for volume of cylinder is given by:

$V = \pi R^{2} H$

Where, R is the radius of base of cylinder

and H is the height of cylinder

We are given that,

$V = \dfrac{36 \pi}{5} ft^{3}$

Using formula for volume, $V = \pi R^{2} H$

$\dfrac{36\pi}{5} = \pi \times 3^{2} \times h\\\Rightarrow \dfrac{36\pi}{5} = \pi \times 9 \times h\\\Rightarrow h = \dfrac{4}{5} ft$

Hence, Height of cylinder is $\frac{4}{5}\ ft$ .

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