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koban [17]
4 years ago
12

Abraham is preparing for a race. He plans to run between 24 and 30 miles a week, either 3 or 4 days a week, and the same number

of miles each day. What are ,begin emphasis,two,end emphasis, possible ways Abraham can complete his running plan? Enter the answers in the boxes. Response area with 2 text input boxes Number of Days Run Miles Run Each Day 3 4
Mathematics
1 answer:
e-lub [12.9K]4 years ago
3 0

Answer: Abraham could run 8 miles each day for 3 days and get 24. He could run 6 miles each day for 4 days and get 24.

Abraham can run 10 miles each day for 3 days and get 30 or he could run 7.5 miles a day for 4 days and get 30.

Not sure if this is the answer it wants or not

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Cosine = Adjacent side ÷ Hypotenuse

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and you get

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4 0
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lidiya [134]

Answer:

Therefore 6th year his income was $19,700.

Step-by-step explanation:

Given, Joe's annual income has been increasing in some dollar amount . The first year his income was $15,200 and 4th  year his income was $17,900.

A=$17900, P= $15,200 and n = 3 year

A= P(1+\frac{r}{100} )^n

\Leftrightarrow 17900=15200(1+\frac{r}{100})^3

\Leftrightarrow (1+\frac{r}{100})^3=\frac{17900}{15200}

\Leftrightarrow (1+\frac{r}{100})=(\frac{17900}{15200})^{\frac{1}{3} }

\Leftrightarrow \frac{r}{100}=(\frac{17900}{15200})^{\frac{1}{3} }-1

\Leftrightarrow r=5.60

Let  t^{th} year Joe's income was $19,700.

\therefore 19700=15,200(1+\frac{5.60}{100} )^{t-1}

\Leftrightarrow 1.296= (1+0.056)^{t-1}

\Leftrightarrow 1.296= (1.056)^{t-1}

\Leftrightarrow  log(1.296)= (t-1)log(1.056)

\Leftrightarrow  \frac{log(1.296)}{log(1.056)}= (t-1)

\Leftrightarrow t-1= 4.75

\Leftrightarrow t= 4.75+1

\Leftrightarrow t = 5.75 ≈6

Therefore 6th year his income was $19,700.

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