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lyudmila [28]
3 years ago
9

Find the derivative of y = arcsin(x)​

Mathematics
2 answers:
natta225 [31]3 years ago
8 0

Answer:

f'(x)= \frac{1}{\sqrt{1-x^{2} } }

Step-by-step explanation:

As khown the derivative of arcsin(x) is;

f'(x)= \frac{1}{\sqrt{1-x^{2} } }

mojhsa [17]3 years ago
7 0

Answer:

1 /√( 1 - x^2).

Step-by-step explanation:

y = arcsin x

x = sin y

dx/dy = cos y

dy/dx = 1 / cos y

Now cos y = √( 1 - sin^2 y)

but sin y = x so

cos y = √( 1 - x^2).

So dy/dx = 1 / √( 1 - x^2).

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Jerry was using matrices to solve the system of three equations. He has shown all his steps. Did he make a mistake if so in what
melomori [17]

There are several ways to solve a system of equation; one of these ways is the use of matrix.

<em>Jerry made a mistake at step 2</em>

From the attachment, the step 1 is represented as:

\mathbf{\frac 12R_1 \left[\begin{array}{cccc}1&1&1&0\\5&3&-2&-4\\3&2&1&1\end{array}\right] }

The equation in step 2 is given as:

\mathbf{R_2 = 5R_1 - R_2}

This means that:

We subtract the elements of row 2 from the elements of row 1, multiplied by 5

So, we have:

\mathbf{R_2 = 5\left[\begin{array}{cccc}1&1&1&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }

Expand

\mathbf{R_2 = \left[\begin{array}{cccc}5&5&5&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }

Subtract corresponding cells

\mathbf{R_2 = \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }

So, the new row 2 elements should be:

\mathbf{ \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }

However, the row 2 elements of Jerry's steps are:

\mathbf{R_2 = \left[\begin{array}{cccc}0&-2&-7&-4\end{array}\right] }

This means that:

Jerry made a mistake; and the mistake is at step 2

Read more about matrix at:

brainly.com/question/21848291

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2 years ago
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Answer:

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Step-by-step explanation:

Use the Distance Formula

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d = sqrt(32)

d = 4*sqrt(2)


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Answer:a)680cu.ft

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Hope this helped you...

Step-by-step explanation:


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