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lyudmila [28]
3 years ago
9

Find the derivative of y = arcsin(x)​

Mathematics
2 answers:
natta225 [31]3 years ago
8 0

Answer:

f'(x)= \frac{1}{\sqrt{1-x^{2} } }

Step-by-step explanation:

As khown the derivative of arcsin(x) is;

f'(x)= \frac{1}{\sqrt{1-x^{2} } }

mojhsa [17]3 years ago
7 0

Answer:

1 /√( 1 - x^2).

Step-by-step explanation:

y = arcsin x

x = sin y

dx/dy = cos y

dy/dx = 1 / cos y

Now cos y = √( 1 - sin^2 y)

but sin y = x so

cos y = √( 1 - x^2).

So dy/dx = 1 / √( 1 - x^2).

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1+1=21+1=21+1=21+1=21+1=21+1=21+1=21+1=21+1=21+1=21+1=2<br><br><br> lol
Vilka [71]

Answer:

1 + 1 equals 2.

Step-by-step explanation:

When you take one of something, and you add it to another 1 of something, then you get 2 of something.

7 0
2 years ago
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How do I find the indicated derivative?
sergey [27]
Multiply the fraction by both things in the parenthesis.
8 0
3 years ago
Jamie is conducting inventory at a public library, so they have to verify that each item from the catalog is in its correct loca
Andrei [34K]

Answer:

Mean: 33.3

SD: 32.8

Step-by-step explanation:

4 0
3 years ago
The hemisphere of radius r is made from a stack of very thin plates such that the density varies with height, r = kz, where k is
Papessa [141]

Answer:

M = ¼ k π R⁴

zG = 8/15 R

Step-by-step explanation:

Note: I'm using lower case r as the radius of each plate and upper case R as the radius of the hemisphere.

The mass of each plate is density times volume:

dm = ρ dV

Each plate has a radius r and a thickness dz.  So the volume of each plate is:

dV = π r² dz

Substituting:

dm = ρ π r² dz

We're told that ρ = kz.  Substituting:

dm = kz π r² dz

Next, we need to write the radius r in terms of the height z.  To do that, we need to look at the cross section (see image below).

The height z and the radius r form a right triangle, where the hypotenuse is the radius of the hemisphere R.

Using Pythagorean theorem:

z² + r² = R²

r² = R² − z²

Substituting:

dm = kπ z (R² − z²) dz

We now have the mass of each plate as a function of its height.  To find the total mass, we integrate between z=0 and z=R.

M = ∫ dm

M = ∫₀ᴿ  kπ z (R² − z²) dz

M = kπ ∫₀ᴿ (R² z − z³) dz

M = kπ (½ R² z² − ¼ z⁴) |₀ᴿ

M = kπ (½ R⁴ − ¼ R⁴)

M = ¼ k π R⁴

Next, to find the center of gravity, we use the weighted average:

zG = (∫ z dm) / (∫ dm)

zG = (∫ z dm) / M

We already found M, we just have to evaluate the other integral:

∫ z dm

∫₀ᴿ kπ z² (R² − z²) dz

kπ ∫₀ᴿ (R² z² − z⁴) dz

kπ (⅓ R² z³ − ⅕ z⁵) |₀ᴿ

kπ (⅓ R⁵ − ⅕ R⁵)

²/₁₅ k π R⁵

Plugging in:

zG = (²/₁₅ k π R⁵) / (¼ k π R⁴)

zG = ⁸/₁₅ R

5 0
3 years ago
Two areas urgent fastttttttttttttttttttttttttttttt
Semmy [17]

Answer:

Rectangle: 112m

Trapezoid: 28m

Step-by-step explanation:

The area of the rectangle is 8*14, which is 112. The area of the trapezoid is ((base1 + base2)* height)/2. That is ((4+10)*4)/2, which is 28.

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2 years ago
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