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Kryger [21]
3 years ago
15

How many solutions exist for the given equation?

Mathematics
2 answers:
faust18 [17]3 years ago
8 0

Answer:

\Huge \boxed{\mathrm{infinite \ solutions}}

Step-by-step explanation:

\sf 12x + 1 = 3(4x + 1) - 2

Using distributive property.

\sf 12x + 1 = 12x+3 - 2

\sf 12x + 1 = 12x+1

Subtracting 1 from both sides.

\sf 12x=12x

Dividing both sides by 12.

\sf x=x

All real numbers are solutions.

There are infinite solutions.

Tpy6a [65]3 years ago
4 0

Answer:

infinitely many

Step-by-step explanation:

12x + 1 = 3(4x + 1) - 2

Distribute

12x + 1 = 12x + 3 - 2

Combine like terms

12x+1 = 12x +1

Subtract 12x from each side

1 =1

Since this is always true, we have infinite solutions

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Answer:

Last Option 48h^{5}.

Step-by-step explanation:

In this question we will do the factors of given two terms then we will do the common factors of all the terms given in answer to match with.

Common factors of 36h³ = 1×2×2×3×3×h×h×h

Common factors of 12h^{6} = 1×2×2×3×h×h×h×h×h×h

In these two terms greatest common factor Of these two terms is = 1×2×2×3×h×h×h = 12h³

Therefore the third term will be the number which has the greatest common factor = 12h³

So the given terms are

6h³ = 1×2×3×h×h×h

12h² = 1×2×2×3×h×h

30h^{4} = 1×2×3×5×h×h×h×h

48h^{5} = 1×2×2×2×2×3×h×h×h×h×h

Therefore the greatest common factor of the term which matches with 12h³ is 48h^{5}

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