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Kryger [21]
3 years ago
15

How many solutions exist for the given equation?

Mathematics
2 answers:
faust18 [17]3 years ago
8 0

Answer:

\Huge \boxed{\mathrm{infinite \ solutions}}

Step-by-step explanation:

\sf 12x + 1 = 3(4x + 1) - 2

Using distributive property.

\sf 12x + 1 = 12x+3 - 2

\sf 12x + 1 = 12x+1

Subtracting 1 from both sides.

\sf 12x=12x

Dividing both sides by 12.

\sf x=x

All real numbers are solutions.

There are infinite solutions.

Tpy6a [65]3 years ago
4 0

Answer:

infinitely many

Step-by-step explanation:

12x + 1 = 3(4x + 1) - 2

Distribute

12x + 1 = 12x + 3 - 2

Combine like terms

12x+1 = 12x +1

Subtract 12x from each side

1 =1

Since this is always true, we have infinite solutions

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