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Tpy6a [65]
2 years ago
7

Whats 5 + 4/23 x -34 Divide by ten is..... P.s. i have to show my work sooooooo.....

Mathematics
2 answers:
Leto [7]2 years ago
8 0

i would guess bruhh tuff

BabaBlast [244]2 years ago
5 0
First, you have to do the multiplication first because pemdas
so 4/23 x (-34) = -136/23
so then do the equation 5 + (-136/23)
after you do that equation the final answer is -21/23
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Solving Exponential Equations (lacking a common base)<br> 4^x-5=8
avanturin [10]

Answer:

x= 6 1/2 or 6.5

Step-by-step explanation:

4^x-5 =8

2^2(x-5) =2^3

since the base is equal, the powers are equal

2(x-5) = 3

2x - 10 = 3

2x = 3 + 10

2x = 13

2x/2 = 13/2

x = 6 1/2 or 6.5

8 0
3 years ago
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#13. 6x — Зу = 8
Ne4ueva [31]

#13

  • 6x — Зу = 8
  • 3y = 6x - 8
  • y = 6/3x - 8/3
  • y = 2x - 8/3
  • The slope = 2
  • The y- intercept = - 8/3

#14

  • 7x = 5y + 2
  • 5y = 7x - 2
  • y = 7/5x - 2/5
  • y = 1.4x - 0.4
  • The slope = 1.4
  • The y- intercept = - 0.4

#15

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  • 6y = 4x - 8
  • y = 4/6x - 8/6
  • y = 2/3x - 4/3
  • The slope = 2/3
  • The y- intercept = -4/3

#16 is not clear

8 0
2 years ago
A triangle can be drawn with angle measure of 60 degrees, 60 degrees, and 70 degrees
GrogVix [38]

Answer:

False. All triangles must have a total of 180°. 60° + 60° + 70° = 190°.

5 0
3 years ago
Can somebody help me plz with this math problem!!
Tema [17]

Answer:

Step-by-step explanation:

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6 0
3 years ago
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An electronics company packages its product in cube-shaped boxes. These boxes are placed into a larger box that measures 3 ft lo
gladu [14]

The number of boxes fitted in the larger container is found out by the volume of both boxes.

The number of boxes fitted into the larger container is 480.

<h3>What is the volume?</h3>

The volume can be defined as the space occupied by an object in three dimensions.

Given that the edge of the cube box is 1/4 ft. The dimensions of the larger box are 3 ft long, 1 1/4 ft wide, and 2 ft.

The volume of the cube box is calculated as given below.

V_s = s^3

Where Vs is the volume of the cube box and s is the edge of the cube box.

V_s = \dfrac {1}{4}^3

V_s = 0.015625\;\rm ft^3

The volume of the larger box is calculated as given below.

<em />V = l \times w\times h

Where V is the volume, l is length, w is width and h is the height of the larger box.

V = 3 \times \dfrac {5}{4} \times 2

V = 7.5\;\rm ft^3

The number of cube boxes fitted into the larger box is calculated as given below.

No. \; of \;boxes = \dfrac {V}{V_s}

No. \; of \;boxes = \dfrac {7.5}{0.015625}

No. \; of \;boxes = 480

Hence we can conclude the number of boxes fitted into the larger container is 480.

To know more about the volume, follow the link given below.

brainly.com/question/1578538.

8 0
2 years ago
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