Answer:
The proportion of scores reported as 1600 is 0.0032
Step-by-step explanation:
Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).
In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)
The values of the cummulative distribution function of the standard Normal random variable, lets denote it are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600
Hence, the proportion of scores reported as 1600 is 0.0032.
The x which achieve these statement is x=0.
Answer:
The answer to your question is: (1/2, -1/3)
Step-by-step explanation:
Elimination
10x - 15y = 10 (I)
4x + 6y = 0 (II)
Multiply (I) by 2 and (II) by -5
20x - 30y = 20
-20x - 30y = 0
Add both equations
0 - 60y = 20
y = -20/60
y = - 1/3
Substitute y in (II)
4x + 6(-1/3) = 0
4x - 2 = 0
4x = 2
x = 2/4
x = 1/2
4(1/2) + 6(-1/3) = 0
4/2 - 6/3 = 0
2 - 2 = 0
0 = 0
Answer:
7 bags
Step-by-step explanation:
We solve using Greatest Common Factor Method
We have:
14 raspberry scones and 21 strawberry scones
We find the factors of 14 and 21
The factors of 14 are: 1, 2, 7, 14
The factors of 21 are: 1, 3, 7, 21
Then the greatest common factor is 7.
Therefore, the greatest number of bags Bryson can fill is 7 bags