Answer:
Below in bold.
Step-by-step explanation:
In each case you divide top and bottom by the GCF.
A. The GCF of 45 and 56 is 1.
so the answer is 45/56.
B. 15/16 (GCF = 1)
C. Here the GCF is 5 so the answer is (35/5) / (80/5)
= 7/16.
D. 5/6 (GCF is 4).
Answer:
14 miles.
Step-by-step explanation:
Let the distance traveled from home to destination = x miles.
Speed while going to friend's house = 35 miles per hour.
Speed while coming back = 40 miles per hour.
Total Time taken for the journey = 45 minutes = 0.75 hours.
Let the time taken while going to friend's house = y hours.
Therefore, the time taken while going to friend's house = (0.75 - y) hours.
To find x and y, model the speeds of both the journeys.
Speed while going to friend's house = Distance/Time.
35 = x/y.
x = 35y (Equation 1).
Speed while coming back = Distance/Time.
40 = x/(0.75 - y).
x = 40(0.75 - y) (Equation 2).
Since x = x, therefore:
35y = 30 - 40y.
75y = 30.
y = 30/75.
y = 0.4 hours.
Put y = 0.4 hours in Equation 1:
x = 35y.
x = 35(0.4).
x = 14.
Therefore, the distance between my friend's house and my house is 14 miles!!!
Answer:
21 3/4
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
Let x=4
Let y=1
4-1=3
8-2=6
