Answer:
broooooooooooo how do you not know that not trying to be rude but anyways the answer is number 3
Answer:
I think it was B I did this yesterday
Step-by-step explanation:
Answer:
![XY = \frac{4\sqrt 3}{3}](https://tex.z-dn.net/?f=XY%20%3D%20%5Cfrac%7B4%5Csqrt%203%7D%7B3%7D)
Step-by-step explanation:
<em>The question is illustrated with the attached figure.</em>
Required
Determine XY
To solve for XY, we make use of the tan function, which states that:
![tan\theta = \frac{Opposite}{Hypotenuse}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7BOpposite%7D%7BHypotenuse%7D)
In this case:
![tan\ 60= \frac{YZ}{XY}](https://tex.z-dn.net/?f=tan%5C%2060%3D%20%5Cfrac%7BYZ%7D%7BXY%7D)
Substitute 4 for YZ
![tan\ 60= \frac{4}{XY}](https://tex.z-dn.net/?f=tan%5C%2060%3D%20%5Cfrac%7B4%7D%7BXY%7D)
Make XY the subject
![XY= \frac{4}{tan\ 60}](https://tex.z-dn.net/?f=XY%3D%20%5Cfrac%7B4%7D%7Btan%5C%2060%7D)
![tan\ 60 =\sqrt 3](https://tex.z-dn.net/?f=tan%5C%2060%20%3D%5Csqrt%203)
So, the expression becomes:
![XY = \frac{4}{\sqrt 3}](https://tex.z-dn.net/?f=XY%20%3D%20%5Cfrac%7B4%7D%7B%5Csqrt%203%7D)
Rationalize:
![XY = \frac{4 * \sqrt 3}{\sqrt 3 * \sqrt 3}](https://tex.z-dn.net/?f=XY%20%3D%20%5Cfrac%7B4%20%2A%20%5Csqrt%203%7D%7B%5Csqrt%203%20%2A%20%5Csqrt%203%7D)
![XY = \frac{4\sqrt 3}{3}](https://tex.z-dn.net/?f=XY%20%3D%20%5Cfrac%7B4%5Csqrt%203%7D%7B3%7D)
Answer:
x = 5
Step-by-step explanation:
because the log is base 2 you can remove the log by raing 2 to the power of each side:
![2^{log2 (3x-7)} = 2^{3}](https://tex.z-dn.net/?f=2%5E%7Blog2%20%283x-7%29%7D%20%3D%202%5E%7B3%7D)
the 2 and log2 cancel leaving:
![3x-7 = 2^{3}](https://tex.z-dn.net/?f=3x-7%20%3D%202%5E%7B3%7D)
this means we can now solve through simple algebra:
![3x-7 = 8\\3x = 8 + 7\\3x = 15\\3x/3 =15/3\\x = 5](https://tex.z-dn.net/?f=3x-7%20%3D%208%5C%5C3x%20%3D%208%20%2B%207%5C%5C3x%20%3D%2015%5C%5C3x%2F3%20%3D15%2F3%5C%5Cx%20%3D%205)
For some number to be divisible by 12 it has to be divisible by 6 and by 2.
we can write number n as:
n = 6 + 12*k where k is positive integer.
If we divide n by 12 we will get remainder 6 because 12*k part is divisible by 12.
The part 12*k is as said divisible by 12 which means it is divisible by 6 (as first stated) and it has remainder 0. That leaves us with 6/6 which again has 0 as remainder. That means that number n is divisible by 6
The answer is 0