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yKpoI14uk [10]
3 years ago
9

(8x + 9) + (15 - 8x)

Mathematics
1 answer:
serious [3.7K]3 years ago
5 0

Answer:

24

Step-by-step explanation:

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WATU
blondinia [14]

Answer:

12.24

Step-by-step explanation:

13.48-1.24=12.24

7 0
3 years ago
What number would complete the pattern below<br> 16 4 12 36 9 27 44 11
Liono4ka [1.6K]
33 is the answer :) Please give me the brainliest answer, and a rate and thanks.
5 0
3 years ago
Which of the following is a nonlinear function?​
mars1129 [50]

The answer is

A. Linda has $1,500 in a bank account that pays 3% annual interest.

3 0
3 years ago
A set of exam scores is normally distributed and has a mean of 80.2 and a standard deviation of 11. What is the probability that
ZanzabumX [31]

Answer:

93.32% probability that a randomly selected score will be greater than 63.7.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80.2, \sigma = 11

What is the probability that a randomly selected score will be greater than 63.7.

This is 1 subtracted by the pvalue of Z when X = 63.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{63.7 - 80.2}{11}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

93.32% probability that a randomly selected score will be greater than 63.7.

5 0
4 years ago
Three numbers are in the ratio 3:9:10. If 10 is added to the last number, then the three numbers form an arithmetic progression.
MrRa [10]

Answer:

<em> The numbers are 6, 18, and 30 </em>

Step-by-step explanation:

If the three numbers are in the ratio of 3:9:10,

let the numbers be 3x, 9x and 10x.

<em>If 10 is added to the last number to form an arithmetic progression</em>

<em>Then, 3x 9x (10x+10) are the progression</em>

The common difference of an arithmetic progression (d) = T₂ - T₁ = T₃ - T₂

T₂-T₁ = T₃ - T₂ .............. Equation 1

Where T₁ = first term of the progression, T₂ = Second term of the progression, T₃ = third term of the progression

<em>Given: T₁ = 3x, T₂ = 9x, T₃ = 10x +10</em>

<em>Substituting these values into equation 1</em>

<em>9x-3x = (10x+10)-9x</em>

<em>Solving the equation above,</em>

<em>3x = 10+x</em>

<em>3x-x = 10</em>

<em>2x = 10</em>

<em>x = 10/2</em>

<em>x = 2.</em>

<em>Therefore the numbers are 6, 18, and 30 </em>

<em />

7 0
4 years ago
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