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GaryK [48]
3 years ago
7

One die is rolled 3 times, what is the chance of getting all 4's?

Mathematics
1 answer:
astraxan [27]3 years ago
4 0
6^3. 216. When using chance, take the possible outcomes(six for a die) and raise it to the power of the number of repetitions.
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On the first day, a company has 64 orders for shipping crates on backorder. Every day customers order 18 more shipping crates. I
SOVA2 [1]

The <em><u>correct answer </u></em>is:

B. 14

Explanation:

Let x be the number of days.  On day 1, we begin with 64 orders.  We gain 18 orders per day; this is 18x, and gives us

64+18x.

We also make 28 crates per day, which decreases the number of crates we need by 28 per day; this is -28x, and gives us

64+18x-28x

Combining like terms, we get

64-10x

For day 5, we replace x with 5:

64-10(5) = 64-50 = 14

4 0
3 years ago
15 = -2 (2t - 1)<br><br> show work and explain
olga_2 [115]
15=-2(2t-1) -- expand brackets
15=-4t+2 -- subtract 2
13=-4t -- switch signs, best to have a positive variable
4t=-13
t=-13/4
7 0
3 years ago
What is the standard for of the number three million, sixty thousand, five hundred twenty?
Juli2301 [7.4K]
3,000,000+60,000+500+20
3 0
3 years ago
Read 2 more answers
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
Please solve will give brainliest
Over [174]

Answer: 12

Step-by-step explanation: Since 11 is ruled out, answer is 12 people

4 0
3 years ago
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