Marie has a building that is 40 feet wide, 70 feet long, and 16 feet high. How many cubic feet of

Find all the missing sides and angles of this triangle,

iren2701 [21]

Answer:

See solutions below

Step-by-step explanation:

From the given diagram;

AC = opposite

AB = 7 = hypotenuse

Angle of elevation = 70 degrees

Using SOH CAH TOA

Sin theta = opp/hyp

Sin theta = AC/AB

Sin 70 = AC/7

AC = 7sin70

AC = 7(0.9397)

AC = 6.58

Similarly

tan 70 = AC/BC

tan 70 = 6.58/BC

BC = 6.58/tan70

BC = 6.58/2.7475

BC = 2.39

tan m<A = BC/AC

tanm<A = 2.39/6.58

tan m<A = 0.3632

m<A = 19.96degrees

8 0

2 years ago

Kebdra has a bag containing 15 marbles. She has 3 white, 8 red, 3 blue 1 green. She randomly picks a marble from the bag and the

prohojiy [21]

Answer:

8/15

Step-by-step explanation:

because there are 8 red marbles out of 15 marbles

5 0

2 years ago

Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads

Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

$Distance = Speed \times Time$

$Distance\ OA = 10 \times 2.5 = 25\ km$

$Distance\ OB = 16 \times 2.5 = 40\ km$

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled $\triangle AOB$ .

According to Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km$

The speed at which distance is increasing between the two boats is given as:

$\dfrac{47.17}{2.5} \approx 18.87\ km/hr$

4 0

2 years ago

A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui

Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= $\frac{dx}{dt}=1. 8 m/s$

$\triangle ABD\sim\triangle ECD$

Therefore, $\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{y}{2}=\frac{12}{x}$

$xy=24$

Differentiate w.r.t t

$x\frac{dy}{dt}+y\frac{dx}{dt}=0$

$x\frac{dy}{dt}=-y\frac{dx}{dt}$

$\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}$

When the man is 4 m from the building

Then, we have x=12-4=8 m

$\frac{dx}{dt}=1.8 m/s$

Substitute the values in above equation then, we get

$8y=24$

$y=\frac{24}{8}=3$

Substitute the values then we get

$\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s$

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0

2 years ago

Taylor wants to figure out how much interest she will earn if she keeps $500 in her savings account for 2 years at a simple annu

Paha777 [63]

Answer:30

Step-by-step explanation:

500*3*2/100=30

4 0

2 years ago

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