Assuming you're running Windows, click the start button, and then search for "Device Manager" (or open CMD or PowerShell and type devmgmt.msc). Look at the list of devices. If Bluetooth is there, you have it; if it's not there, you don't.
Answer:
theoretically yes. we would need to cross and langue gap because our brain signals wouldn't understand words
Explanation:
educated quess
Answer:
import java.util.Scanner;
public class Solution {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter your value");
int value = scan.nextInt();
greaterThanFive(value);
}
public static void greaterThanFive(int userInput){
System.out.println(userInput > 5);
}
}
Explanation:
The first line import the Scanner which is use to enable to accept user input.
The class is defined as Solution in the next line. The main method is declared in the next line which signify the beginning of the program.
Then, a scanner object is declared called scan in the next line. Then a prompt is display to the user to input a value. The user input is stored in the variable value. The value is then passed to the method greaterThanFive.
The method greaterThanFive is declared and have just one parameter, the userInput. Inside the method, we output if the userInput is greater than 5 using the logical operator (>).
Answer:
B. Fifa Soccer
Explanation:
That should be your answer.
Answer:
11 bit slot will be needed
Explanation:
The number of prime numbers between 1 through 16
= 2, 3 , 5, 7, 11 and 13
hence we can say 6 stations are to use the shared channel
Given that all the stations are ready simultaneously
The number of bit slots that will be needed to handle the contention will be 11 bits :
slot 1 : 2, 3, 5 , 7, 11 , 13
slot 2 : 2,3, 5, 7
slot 3 : 2, 3
slot 4 : 2 . slot 5 : 3 . slot 6 : 5,7. slot 7 : 5 . slot 8 : 7. slot 9: 11,13.
slot 10 : 11. slot 11 : 13
