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klasskru [66]
2 years ago
5

Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t

o 50 characters, simply reprint the line. For lines greater than 50 characters, insert a newline at each 50-character interval.
Note: If the 51st character of a line in the input is a newline '\n', then you should not print it (to avoid unnatural double newlines in the text). Depending on your solution, you may not need extra code for this. So worry about this case last.

Tip: Write your own file with test input for the case where the 51st character is a newline. In the bottom-right corner of Vim, you can see the line and column number of your cursor and plan your 51-character input accordingly.

Furthermore, to give developers feedback on their programs for 50-character-displays, you decide to add additional functionality to your program by displaying the line numbers of all lines over 50 characters long and the total number of these offending lines.

For example:

learncli$ cat test0.txt
This line is under 50 characters long
This line is just over 50 characters long, you see?
This line is soooooooooooooooooo looooouoooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooong!

learncli$ cat test0.txt | ./a.out
This line is under 50 characters long
This line is just over 50 characters long, you see
?
This line is soooooooooooooooooo looooouoooooooooo
oooooooooooooooooooooooooooooooooooooooooooooooooo
oooooong!

Total lines over 50 chars: 2
Offending lines: 1, 2,
learncli$
Computers and Technology
1 answer:
Alex73 [517]2 years ago
4 0

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

<em>#include<stdio.h></em>

<em />

<em>int main(int argc, char** argv){</em>

<em>    //creating pointer to read a file</em>

<em>    FILE * fp;</em>

<em>    char * line = NULL;</em>

<em>    size_t len = 0;</em>

<em>    ssize_t read;</em>

<em>    int i=0;</em>

<em>    //opening a file</em>

<em>    fp = fopen(argv[1], "r");</em>

<em>    //handling the error condition</em>

<em>    if (fp == NULL){</em>

<em>        printf("File not found..!!");</em>

<em>        return 0;</em>

<em>    }</em>

<em>    int moreThan50 =0;</em>

<em>    //reading a file line by line</em>

<em>    while ((read = getline(&line, &len, fp)) != -1) {</em>

<em>        i = 0;</em>

<em>        if(read >= 50){</em>

<em>            moreThan50++;</em>

<em>        }</em>

<em>        while(i < read){</em>

<em>            if(line[i]!='\n'){</em>

<em>                if(i%50 == 0){</em>

<em>                    printf("\n%c",line[i]);</em>

<em>                }else{</em>

<em>                    printf("%c",line[i]);</em>

<em>                }</em>

<em>            }</em>

<em>            i++;</em>

<em>        }</em>

<em>    }</em>

<em>    printf("\nTotal lines over 50 chars: %d\n",moreThan50);</em>

<em>    printf("Offending Lines: ");</em>

<em>    for(i=1;i<=moreThan50;i++)</em>

<em>        printf("%d, ",i);</em>

<em>    fclose(fp);</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

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The correct answer for the given question is Integer.parseInt( string variable );

Explanation:

Integer.parseInt( string variable ); is the method in a java programming language that convert the string into the integer value. It takes a string variable and converted into the integer.

Following are the program in java which convert the string value into an integer value.

class Main  

{

 public static void main(String []args) // main function

{

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// variable declaration

   int k = Integer.parseInt(str1);

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Converted into Int:10009

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