19.05*10 power 5
hope it helps
It looks like you want to compute the double integral

over the region <em>D</em> with the unit circle <em>x</em> ² + <em>y</em> ² = 1 as its boundary.
Convert to polar coordinates, in which <em>D</em> is given by the set
<em>D</em> = {(<em>r</em>, <em>θ</em>) : 0 ≤ <em>r</em> ≤ 1 and 0 ≤ <em>θ</em> ≤ 2<em>π</em>}
and
<em>x</em> = <em>r</em> cos(<em>θ</em>)
<em>y</em> = <em>r</em> sin(<em>θ</em>)
d<em>x</em> d<em>y</em> = <em>r</em> d<em>r</em> d<em>θ</em>
Then the integral is

Answer:
vertex = (- 3, 5 )
Step-by-step explanation:
The general form of the absolute value function is
y = a | x - h | + k
where (h, k) are the coordinates of the vertex
Given
y = - | x + 3 | + 5 ← in general form, then
vertex = (- 3, 5 )
Answer:
1+1= 2
have a nice day stay safe
Answer:
15
Step-by-step explanation:
