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2 years ago

4x - x, for x=2 WHATS THE ANSWER

Mathematics

2 answers:

pishuonlain [190]2 years ago

8 0

The answer is 6 4(2)=8 -2 = 6

Vesna [10]2 years ago

8 0

Input 2 as x!

so (4•2)-2
8-2=6

The answer is 6!

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What is the product of the binomials (4a – 1) and (2b + 3)?

galben [10]

Answer:

D. 8ab+12a-2b-3

Step-by-step explanation:

You are basically combining like terms

8 0

2 years ago

Read 2 more answers

Find the area of the shaded region.

Papessa [141]

Answer:

21.46 cm²

Step-by-step explanation:

because the question want only for the SHADED REGION but NOT AREA OF THE SQUARE

(if we just multiply 10x10. you will get the area of a square which is hundered)

To find the shaded region:

1. area of a circle is πr² (we have 4 circle there)

2. Find the area of all circle

# how do we know the radius?

- half of 10 is 5

- 5 is the diameter of each circle

- the radius is half of 5 which is 2.5

- π(2.5)² = 25/4π (area of 1 circle)

3. since we have 4 circle then, 25/4π x 4 = 25π

4. the area of the square is 100cm²

5. we want the shaded region so we have to minus the area of the circle

6. 100 - 25π (use your calculator to find the answer)

answer should be 21.46 cm²

(hope this helps)

8 0

3 years ago

On a coordinate plane, a line is drawn from point a to point b. point a is at (negative 8, negative 13) and point b is at (4, 11

vladimir2022 [97]

The coordinate for point P which is one-third the length of the line segment from a to b is (-4, -5)

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Point a is at (-8, -13) and point b is at (4, 11). Hence the coordinates for point p(x, y) which is one-third the length of the line segment from a to b is:

$x=\frac{1}{3}(4-(-8))+(-8)=-4\\ \\y=\frac{1}{3}(11-(-13))+(-13)=-5$

The coordinate for point P which is one-third the length of the line segment from a to b is (-4, -5)

Find out more on equation at: brainly.com/question/2972832

#SPJ4

7 0

1 year ago

Write the equation of the circle in standard form: Center (7,0) R=1

Mice21 [21]

Answer:

$(x-7)^2+y^2=1$

Step-by-step explanation:

Hi there!

Equation of a circle: $(x-h)^2+(y-k)^2=r^2$ where the circle is centered at (h,k) and the radius is r

<u>1) Plug in the given center (7,0)</u>

$(x-7)^2+(y-0)^2=r^2\\(x-7)^2+y^2=r^2$

<u>2) Plug in the radius (1)</u>

$(x-7)^2+y^2=1^2\\(x-7)^2+y^2=1$

I hope this helps!

8 0

2 years ago

Integration of the following function

DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

$\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}$

$d\bar{c}=\left ( -6x^{-2}+\frac{1}{6}\right )dx$

Now, integrating both sides

$\int d\bar{c}=\int \left ( -6x^{-2}+\frac{1}{6}\right )dx$

$\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1$

$\bar{c}=6x^{-1}+\frac{1}{6}x+k_1$

6 0

2 years ago