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2 years ago

DUE TODAY: PLEASE HELP

Mathematics

1 answer:

BabaBlast [244]2 years ago

5 0

Answer:

See below ~

Step-by-step explanation:

We need to prove that the figures are similar by applying the various kinds of transformations.

===============================================================

Question A :

⇒ Compare the side lengths of A and B

⇒ 2 : 5 (for all sides)

⇒ <u>1 : 2.5</u>

⇒ Hence, Shape A has been dilated with a scale factor of 2.5 to form Shape B

=============================================================

Question B :

⇒ Compare the side lengths of A and B

⇒ A : B = 2 : 6

⇒ A : B = <u>1 : 3</u>

⇒ Shape A has been dilated with a scale factor of 1/3 to form Shape B

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tangare [24]

Not sure what form you want this in:

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2 years ago

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viktelen [127]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c$

____________________________________

$\large \tt Solution \: :$

Vector d can be represented as :

$\qquad \tt \rightarrow \: - 2 \hat i - 2 \hat j$

Vector c can be represented as :

$\qquad \tt \rightarrow \: 4 \hat i + 4\hat j$

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

$\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) = - 2 \hat i - 2 \hat j$

$\qquad \tt \rightarrow \: x = - ( 4 \hat i + 4 \hat j) - 2 \hat i - 2 \hat j$

$\qquad \tt \rightarrow \: x = (- 4 \hat i - 2 \hat i) + ( - 4 \hat j - 2 \hat j)$

$\qquad \tt \rightarrow \: x = - 6 \hat i -6 \hat j$

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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2 years ago

What is 7.8×10^5 hours in days?

iragen [17]

Answer:

32500 Days

Step-by-step explanation:

$7.8$ × $10^{5}$ = $780000$

We know that there are 24 hours in a day.

⇒24 Hours = 1 Day

therefore $780000$ hours = $\frac{780000}{24} = 32500$ Days

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Alenkinab [10]

I think that it is c or d but correct me if i am wrong

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alexandr402 [8]

52 miles is the right question for this one!

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3 years ago