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3 years ago

PLZZ HELP ILL GIVE BRAINLYEST PLZZ HELP

Engineering

2 answers:

Roman55 [17]3 years ago

7 0

Whatever ur designing has to fit the requirements.

Serhud [2]3 years ago

4 0

Answer:

If someone requires you to do something, like no blue, you have to change the blue to another color.

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Suppose that a one-celled organism can be in one of two states – either A or B. An individual in state A will change to state B

xxTIMURxx [149]

Answer:

P{x,y} {x - 1, y + 1} = βy/ αx + βy.

P{x,y} {x + 1, y - 1} = βx/ αx + βy.

Explanation:

The full meaning for the acronym "CTMC" given in the question is known as the continuous-time Markov chain. The continuous-time Markov chain is an important tool or instrument which is used in the dealings with stochastic process.

Hence, Xa(t) is the number of organisms in state A, Xb(t) is the number of organisms in state B. Therefore, we can say that the continuous-time Markov chain(CTMC) is;

{ Xa(t), Xb(t)}.

Thus, b(x,y) = αx + βy.

Therefore, we will have;

P{x,y} {x - 1, y + 1} = βy/ αx + βy.

P{x,y} {x + 1, y - 1} = βx/ αx + βy.

Note that, if we are to use the generation of matrix to get differential equation as below;

I(x)α(ix - 1, iy + 1) (JxJy)(t) + iyβ

P (ix + 2, iy -1) (Jx,Jy) (t) - (ixα + iyβ) P(ix,iy)(JxJy) (t).

t is greater or equals to zero for ix,iy, Jx and Jy.

3 0

3 years ago

Car B is traveling a distance dd ahead of car A. Both cars are traveling at 60 ft/s when the driver of B suddenly applies the br

vagabundo [1.1K]

Answer:

Explanation:

Using the kinematics equation $v = v_o + a_ct$ to determine the velocity of car B.

where;

$v_o =$ initial velocity

$a_c$ = constant deceleration

Assuming the constant deceleration is = -12 ft/s^2

Also, the kinematic equation that relates to the distance with the time is:

$S = d + v_ot + \dfrac{1}{2}at^2$

Then:

$v_B = 60-12t$

The distance traveled by car B in the given time (t) is expressed as:

$S_B = d + 60 t - \dfrac{1}{2}(12t^2)$

For car A, the needed time (t) to come to rest is:

$v_A = 60 - 18(t-0.75)$

Also, the distance traveled by car A in the given time (t) is expressed as:

$S_A = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2$

Relating both velocities:

$v_B = v_A$

$60-12t = 60 - 18(t-0.75)$

$60-12t =73.5 - 18t$

$60- 73.5 = - 18t+ 12t$

$-13.5 =-6t$

t = 2.25 s

At t = 2.25s, the required minimum distance can be estimated by equating both distances traveled by both cars

i.e.

$S_B = S_A$

$d + 60 t - \dfrac{1}{2}(12t^2) = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2$

$d + 60 (2.25) - \dfrac{1}{2}(12*(2.25)^2) = 60 * 0.75 +60((2.25)-0.75) -\dfrac{1}{2}*18*((2.25)-0.750)^2$

d + 104.625 = 114.75

d = 114.75 - 104.625

d = 10.125 ft

3 0

3 years ago

If you have held a learner's license for more than three months, you may NOT drive _____.

Alex

Answer

Learner's license expires after six months of the date of issue

Explanation:

The learner's license issued to make a person eligible to learn driving in a given time period. In India the learning license is valid for six months after the issuing date but the person have to apply for the driving license within the three months of the issued date. You can drive the vehicles listed in the learner's license document even after the three months of the issuing date. The process of obtaining a driving license have certain process

Go to the online web portal of your state driving license authority apply for the driving license and print the application form page from there.
Attach this application form and RED CROSS certificate with the file given by the R.T.O office and submit this to them.

The authority will give you date, time and site of the driving test where you have to got there with your vehicle for the test.
If you passes the driving test your file will pass and you can take your driving license after some days from the R.T.O office.

7 0

3 years ago

Read 2 more answers

Why do computers use 1 and 0

tangare [24]

I like ya cut g

Explanation:

bonK no Uhm

6 0

3 years ago

Read 2 more answers

If pure oxygen is fed in excess by 25%, what would the fractional conversion of methane be for the final concentration of CO2 in

inessss [21]

Answer:the fractional conversion of methane is 12.5%

Explanation:The reaction represent the combustion of methane to produce Co2 and steam.

CH4 +2O2_CO2 + 2H2O

From gay lussac law of proportionality

1mol of CH4 requires 2mol of Oxygen to produce 1 mol of CO2 and 2mol of H2O

So from the combining ratio,25% of O2 will fractional produce 25×1/2% of CH4.

While 12.5% of CO2 and 25% of steam is also produced .so in essence 2.5% of CO2 was lost in the reaction.

7 0

4 years ago