Answer:
the elongation of the metal alloy is 21.998 mm
Explanation:
Given the data in the question;
K = σT/ (εT)ⁿ
given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,
strain-hardening exponent n = 0.22
we substitute
K = 345 / 
K = 815.8165 Mpa
next, we determine the true strain
(εT) = (σT/ K)^1/n
given that σT = 412 MPa
we substitute
(εT) = (412 / 815.8165 )^(1/0.22)
(εT) = 0.04481 mm
Now, we calculate the instantaneous length
= 
given that 
= 480 mm
we substitute
=
× 
= 501.998 mm
Now we find the elongation;
Elongation = 
we substitute
Elongation = 501.998 mm - 480 mm
Elongation = 21.998 mm
Therefore, the elongation of the metal alloy is 21.998 mm
Answer:
F(x) = 0 ; x < 0
0.064 ; 0 ≤ x < 1
0.352 ; 1 ≤ x < 2
0.784 ; 2 ≤ x < 3
1 ; x ≥ 3
Explanation:
Each wafer is classified as pass or fail.
The wafers are independent.
Then, we can modelate X : ''Number of wafers that pass the test'' as a Binomial random variable.
X ~ Bi(n,p)
Where n = 3 and p = 0.6 is the success probability
The probatility function is given by :
Where 
is the combinatorial number
Let's calculate f(x) :
For the cumulative distribution function that we are looking for :
The cumulative distribution function for X is :
F(x) = 0 ; x < 0
0.064 ; 0 ≤ x < 1
0.352 ; 1 ≤ x < 2
0.784 ; 2 ≤ x < 3
1 ; x ≥ 3
Answer:
An isolation transformer whose main purpose is to reduce voltage spikes will have a turns ratio of 1 to 1.
This is due to the windings input and output having the same waveform and amplitude.
Answer:
True
Explanation:
True - because different classification of steel beam have different yield strength.
The moment capacity for a steel beam is given by;
M = Mn / Ωₙ
where;
M - the maximum moment acting on the beam
Ωₙ - is the Safety Factor for Elements in Bending = 1.67
Mn - nominal moment of the steel, given as
where;
Zₓ - the Plastic Section Modulus in the x or strong axis.
is the Yield Strength of the Steel (A36W, A46 W or A50W)
A36W = 36 ksi
A46 W = 46 ksi
A50W = 50 ksi
Thus, before you calculate the moment capacity for a steel beam, you have to determine the classification of beam, for the yield strength of the steel beam.
Answer:
a) True
Explanation:
Roller can provide reaction for push support but it can not provide reaction for pull support.
From the free body diagram of roller and hinge support we can easily find that ,Roller providing vertical reaction and can not provide horizontal reaction.
On the other hand hinge support can provide reaction in both the direction.
So we can say that roller can not proved reaction for pull support.
