An adiabatic air compressor is to be powered by a direct coupled adiabatic steam turbine that is also driving a generator. Steam
1 answer:
You might be interested in
Answer:
B) 2.22
Explanation:
In a first step, the system will look in cache number 1. If it is not found in cache number 1, then the system will look in cache number 2. Finally (if not in cache 2 also) the system will look in main memory.
The average access time will take into consideration success in cache 1, failure in cache number 1 but success in cache number 2, failure in cache number 1 and 2 but success in main memory.
Mathematically we can write it into the following equation :
Where AAT is the average access time
H1,H2 and Hm are the hit rate of cache 1,cache 2 and main memory respectively.
T1,T2 and Tm are the access time of cache 1, cache 2 and main memory respectively
Hm = 1
Therefore, option b) is the correct.
Answer:
Part A:
In W-h:
Energy Stored=1440 W-h
In Joules:
Part B:
In W-h:
Energy left=240 W-h
In Joules:
Energy left= 8.64*10^5 J
Explanation:
Part A:
We are given rating 120A-h and voltage 12 V
Energy Stored= Rating*Voltage (Gives us units W-h)
Energy Stored=120A-h*12V
Energy Stored=1440 W-h
Converting it into joules (watt=joules/sec)
Energy Stored=
Energy Stored=5184000 Joules
Part B:
Energy used by lights for 8h=150*8
Energy used by lights for 8h=1200W-h
Energy left= Energy Stored(Calculated above)- Energy used by lights for 8h
Energy left=1440-1200
Energy left=240 W-h
Energy left=
Energy left=864000 Joules
Energy left= 8.64*10^5 J