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iren2701 [21]
3 years ago
12

Jane has three boxes she needs to ship. Box X weighs 33 kg more than Box Y and Box Z weighs 12 kg more than Box Y. She

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

3w+45=557

Step-by-step explanation:

Let the weight of box Y be w kg.

Box X weighs 33 kg more than Box Y, then the weight of box X is

w+33 kg.

Box Z weighs 12 kg more than Box Y, then the weight of box Z is

w+12 kg.

The total weight of all boxes is

w+(w+33)+(w+12)=w+w+33+w+12=3w+45 kg

Jane measured the total weight of all the boxes and it was found to be 557 kg, therefore,

3w+45=557

or

3w=512

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Step-by-step explanation:

Let us equate the fraction by its equivalent

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→ Multiply both sides by (x - 10) to cancel the denominator of the left side

∴  \frac{352}{x-10}  × (x - 10) = -22 × (x - 10)

∴ 352 = -22(x - 10)

→ Simplify the right side by multiplying -22 by the bracket (x - 10)

∵ 352 = -22(x) - 22(-10)

∴ 352 = -22x + 220

→ Add 22x to both sides

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