find the value of x2 values that separate the middle 90% from the rest of the distribution for 8 degrees of freedom
1 answer:
Answer:
With alpha 0.95 and 8 degrees of freedom χ²= 2.73
And with alpha 0.05 and 8 degrees of freedom χ²=15.51
Step-by-step explanation:
The significance level ∝ = 1- 0.9 = 0.1
But we need the area of the middle so we divide this significance level with 2
so that we get exactly the middle area .
Dividing 0.1/2= 0.05
So we will have two values for chi square
One with 0.9 + 0.05 = 0.95 alpha and one with 0.05 alpha . This is because the chi square is right tailed.
So with alpha 0.95 and 8 degrees of freedom χ²= 2.73
And with alpha 0.05 and 8 degrees of freedom χ²=15.51
This can be shown with a graph.
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Answer:
The correct option is c.
Step-by-step explanation:
Linear function: The rate of change of a linear function is always constant.
Non-Linear function: The rate of change of a non-linear function is not constant.
From the given coordinate pairs it is noticed that the function is passing through the points (0,-100), (1,-50), (2,0), (3,100) and (4,150).
The slope of function for points (0,-100) and (1,-50) is
The slope of function for points (2,0) and (3,100) is
Since the slopes of function are different, therefore the given function is non-linear.
The function is not linear because the rate of change is not constant and option c is correct.
Answer:
Step-by-step explanation:
An ellipse with vertices (-8, 0) and (8, 0)
Distance between two vertices = 2a
Distance between (-8,0) and (8,0) = 16
2a= 16
so a= 8
Vertex is (h+a,k)
we know a=8, so vertex is (h+8,k)
Now compare (h+8,k) with vertex (8,0) and find out h and k
h+8 =8, h=0
k =0
a minor axis of length 10.
Length of minor axis = 2b
2b = 10
so b = 5
General formula for the equation of horizontal ellipse is
a= 8 , b=5 , h=0,k=0. equation becomes