Points on given line = (-12,-2) and (0,-4) because you can see them on the graph. Then draw a parallel line thru (0,6)
To get from (0,-4) to (0,6) your x stays constant and your y coordinate increased by 10. So your new point will do the same in relation to (-12,-2) the x will stay constant at -12 and your y will increase by 10 to +8.
So the answer is A (-12,8)
You can check this because parallel lines have the same slope so
y2-y1/x2-x1 should be equal for both lines.
Line 1: -4 - (-2) / 0 - (-12) = -2/12 = -1/6
Line 2: 6 - 8 / 0 - (-12) = -2/12 = -1/6
I will be able to answer this question, if it wasn't sideways
U have to multiply and then divide it and find that scale
Answer:
No, the Roger’s claim is not correct.
Step-by-step explanation:
We are given that Roger claims that the two statistics most likely to change greatly when an outlier is added to a small data set are the mean and the median.
This statement by Roger is incorrect because the median is unaffected by the outlier value and only the mean value gets affected by the outlier value.
As the median represents the middlemost value of our dataset, so any value which is an outlier will be either at the start or at the end will not the median value. So, the median will not likely change when an outlier is added to a small data set.
Now, the mean is the average of all the data set values, that is the sum of all the observations divided by the number of observations. The mean will get affected by the outlier value because it take into account each and every value of the data set.
Hence, the mean will likely to change greatly when an outlier is added to a small data set.
