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BARSIC [14]
3 years ago
14

The graph of f(x) = |x| is transformed to g(x) = |x + 1| – 7. On which interval is the function decreasing?

Mathematics
2 answers:
vichka [17]3 years ago
8 0

Answer:

(-\infty,-1) interval is the function decreasing.

Step-by-step explanation:

Given : The graph of f(x) = |x| is transformed to g(x) = |x+1|-7

To find : On which interval is the function decreasing?

Solution :

First we plot the graph of both the functions,  

The graph of f(x) = |x| is shown with black line.

The graph of g(x) = |x+1|-7  is shown with violet line.

Refer the attached figure below.

The graph shows the interval over which it is increasing or decreasing.

As we notice it is increasing on the interval (-1,\infty)

Decreasing on (-\infty,-1)

Therefore, (-\infty,-1) interval is the function decreasing.

SOVA2 [1]3 years ago
5 0

Answer:

(–∞, –1) is the answer

Step-by-step explanation:


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2 years ago
Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =
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Answer:

c = 5

Step-by-step explanation:

Given

f(c) = M

f(x) = x^2 - x + 1

Interval: [1,8]

M = 21

Required

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First, check if the value of M is within the given range:

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Solving further:

We have:

f(c) = f(x) = M

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Substitute 21 for f(x) in f(x) = x^2 - x + 1

21 = x^2 - x + 1

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Expand

x^2 + 4x - 5x - 20

x(x+4)-5(x+4)=0

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The value of x = -4 is outside the Interval: [1,8]

So:

x = 5

f(c) = f(x) = M

f(c) = f(5) = 21

By comparison:

c = 5

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